Answer:
An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:
Step-by-step explanation:
Given the points
Finding the slope between the points (-4,1) and (4,3)
Refine
Point slope form:
where
- m is the slope of the line
in our case,
substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.
Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:
Answer:
b not shure tho so yeah bye anwser is B
Answer:
Step-by-step explanation:
<u>Given equation:</u>
- x² + y² + 8x - 4y - 7 = 0
<u>Convert this to standard form by completing the square:</u>
- (x - h)² + (y - k)² = r², where (h, k) - center, r - radius
- x² + 2*4x + 4² + y² - 2*2y + 2² - 16 - 4 - 7 = 0
- (x + 4)² + (y - 2)² - 27 = 0
- (x + 4)² + (y - 2)² = 27
- (x + 4)² + (y - 2)² = (√27)²
The center is (- 4, 2) and the radius is √27
Answer:
To create function h, function f was translated 2 units to the right, translated 4 units down and reflected across the y-axis.
Step-by-step explanation:
Since f(x) = x^3 is transformed to h(x) = -(x+2)^3-4, by
1. Adding 2 to x in x³ to give f'(x) = f(x + 2) = (x + 2)³.
2. We now translate f(x + 2) down by subtracting 4 from f(x + 2) to give
f''(x) = f'(x) - 4 = f(x +2) - 4 = (x + 2)³ - 4.
3. We now reflect f'(x) across the y-axis by multiplying (x + 2)³ by -1 to get
h(x) = -(x + 2)³ - 4.
