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luda_lava [24]
3 years ago
14

A car service charges a fixed fee of $3 plus $2 for each mile. Find the cost of a 7-mile ride. Let x=the number of miles.

Mathematics
2 answers:
omeli [17]3 years ago
6 0
3 + 2x = 17 
3 + 2 times 7 miles (x) = 17
Hope this helps!!
Cloud [144]3 years ago
5 0
3 + 2x = 17

3 + 2x = 17



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Find an expression for the nth term -3 , 2 , 7, 12​
slavikrds [6]

Answer:

5n-8

Step-by-step explanation:

Because this is an arithmetic progression, there is simply an addend that is being added to every number. Because that is 5, the expression, for now, would be 5n. However, the progression does not start at 0, so we will have to subtract 3, and then it would be 5n - 3. We're still not at the answer; this is because the first term starts at 1, not 0. We will have to account for that, so subtract the coefficient, or 5, from the whole expression. That would be 5n - 8, and that would be the answer.

4 0
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Can someone that will GIVE ME A GOOD ANSWER can you help me please
jenyasd209 [6]

Answer:  -3 bc the exponent is adding -1 each time

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3 years ago
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sertanlavr [38]
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Solve using the quadratic formula or factoring ... 5=6x^2 + 13x
FromTheMoon [43]

Answer:

x = \frac{-5}{2} <u><em>or  </em></u>x = \frac{-1}{3}

Step-by-step explanation:

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Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

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Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
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