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2 years ago

11

Not sure how to do this! I’m supposed to find the area of each shape, but the slits in the shapes are confusing me and I’m not t

oo sure how to do these problems!

1 answer:

scoray [572]2 years ago

4 0

sorry i don't know answe're of this question

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Jones of Boston borrowed $40,000, 90 day, 10% note. After 60 days Jones made an initial payment of $6,000. Assuming the U.S. Rul

nadezda [96]

check a website called math-way without the dash it might help

6 0

3 years ago

A construction crew has repaired 1.37 miles of a highway. The total length of the highway to be repaired is 7.9. How many miles

JulijaS [17]

Answer:

Part A: m+1.37=7.9

Part B: 6.53 miles are left to be repaired.

Step-by-step explanation:

Given,

Length of repaired part = 1.37 miles

Total length to be repaired = 7.9 miles

Miles left to be repaired = m

Part A:

Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.

Miles left to be repaired + Length of repaired part = Total length to be repaired

m+1.37=7.9

Part B

How many miles are left to be repaired?

Subtracting 1.37 from both sides

6.53 miles are left to be repaired.

Keywords: length, subtraction

Step-by-step explanation:

6 0

2 years ago

Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha

kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable $X$ follows a Poisson distribution $P(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda$

Evaluate the formula at $k=2,3:$

$P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}$

#since

$4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda$

The mean and variance of the Poisson distributed random variable is equal to $\lambda$ :

$\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75$

#By property variance:

$\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125$

The expectation is 1.3125

4 0

3 years ago

Help me plss, number 2.

Gnesinka [82]

Answer:

At (-2,0) gradient is -4 ; At (2,0) gradient is 4

Step-by-step explanation:

For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).

y = x^2 - 4

y' = 2x

The function y = x^2 - 4 cross the x-axis when:

y = x^2 - 4

0 = x^2 - 4

4 = x^2

2 +/- = x

Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).

The gradient at these points are as follows:

y' = 2(-2) = -4

y' = 2(2) = 4

Cheers.

3 0

3 years ago

Jack reads his book for 8 minutes before school and 10 minutes after school. He attends school Monday through Friday. Which equa

sweet-ann [11.9K]

Answer:

<h2>90 min or 1hr 30 mins</h2>

Step-by-step explanation:

Even though the options to choose from are not given in this question we can try and lay our hand on the most likely equation for the number of minutes Jack reads his book.

firstly on a daily Jack reads a total of = 8+10 = 18 mins

He attends school from Mon- fri = 5 days

Now on a weekly basis jack reads = 5*18

in other words, the equation is simply the number of days times the time spent to read his book per day

hence this is = 90 min or 1hr 30 mins

5 0

3 years ago