Answer:
- left: a, 0.4A; b, 0.4A; c, 0.4A; d, 0.4A; e, 0.8A
- right: a, 0.4A; b, 0.2A; c, 0.4A, d, 0.2A; e, 0.6A
Step-by-step explanation:
The currents into and out of a single device are the same. The sum of currents into and out of a junction are the same.
<u>Left Circuit</u>
The two branches at the bottom of the circuit are identical, so will have the same current. The current in each branch will be half the current shown coming from the battery:
a = b = c = d = (0.8 A)/2 = 0.4 A
The current at e into the battery will be the same as the current shown coming out of the battery:
e = 0.8 A
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<u>Right Circuit</u>
0.6 A is the sum of the currents into the two branches. The current in the bottom branch is shown as 0.2 A, so the current in the top branch must be 0.4 A. That way, the currents total 0.6 A.
As before, the current throughout any given branch is the same, so ...
a = c = 0.4 A
b = d = 0.2 A
e = 0.6 A
