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2 years ago

Answer for both for brainliest

Mathematics

1 answer:

iragen [17]2 years ago

3 0

Answer:

left: a, 0.4A; b, 0.4A; c, 0.4A; d, 0.4A; e, 0.8A
right: a, 0.4A; b, 0.2A; c, 0.4A, d, 0.2A; e, 0.6A

Step-by-step explanation:

The currents into and out of a single device are the same. The sum of currents into and out of a junction are the same.

Left Circuit

The two branches at the bottom of the circuit are identical, so will have the same current. The current in each branch will be half the current shown coming from the battery:

a = b = c = d = (0.8 A)/2 = 0.4 A

The current at e into the battery will be the same as the current shown coming out of the battery:

e = 0.8 A

Right Circuit

0.6 A is the sum of the currents into the two branches. The current in the bottom branch is shown as 0.2 A, so the current in the top branch must be 0.4 A. That way, the currents total 0.6 A.

As before, the current throughout any given branch is the same, so ...

a = c = 0.4 A

b = d = 0.2 A

e = 0.6 A

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gavmur [86]

Answer:

Number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

Step-by-step explanation:

We are given that one wants to estimate the mean PSLT for the population of all families in New York City with gross incomes in the range $35.000 to $40.000.

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Here, we will use the concept of Margin of error as the statement "true mean PSLT within 0.5" represents the margin of error we want.

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Margin of error = $Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }$

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n = number of families

Now, in the z table the critical value of x at 5% ( $\frac{0.10}{2} = 0.05$ ) level of significance is 1.645.

SO, Margin of error = $Z_(_\frac{\alpha}{2}_ ) \times \frac{\sigma}{\sqrt{n} }$

0.5 = $1.645 \times \frac{2}{\sqrt{n} }$

$\sqrt{n} =\frac{2\times 1.645 }{0.5}$

$\sqrt{n} =6.58$

n = $6.58^{2}$

= 43.3 ≈ 43

Therefore, number of families that should be surveyed if one wants to be 90% sure of being able to estimate the true mean PSLT within 0.5 is at least 43.

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