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yanalaym [24]
3 years ago
14

If you Buy my group clothing in R.o.b.l.o.x for a donation i will make you brainliest

Computers and Technology
2 answers:
erastova [34]3 years ago
7 0

Answer:kk ima do it

Explanation:

joja [24]3 years ago
4 0

Answer:

this and that

Explanation:

this and that

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Computer science practical on VB.NET. program 1. program to find the square of a number. write the code achieve it​
Korvikt [17]

Answer:

Module Program

   Sub Main()

       Dim num As Integer

       num = 4

       Console.WriteLine("The square of " & num & " is " & num * num)

       Console.ReadKey()

   End Sub

End Module

Explanation:

Very similar to the other program you posted.

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What would you have to know about the pivot columns in an augmented matrix in order to know that the linear system is consistent
Scrat [10]

Answer:

The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

Then satisfying this theorem the system is consistent and has one single solution.

Explanation:

1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

rank(A)

Then the system is consistent and has a unique solution.

<em>E.g.</em>

\left\{\begin{matrix}x-3y-2z=6 \\ 2x-4y-3z=8 \\ -3x+6y+8z=-5  \end{matrix}\right.

2) Writing it as Linear system

A=\begin{pmatrix}1 & -3 &-2 \\  2& -4 &-3 \\ -3 &6  &8 \end{pmatrix} B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}

rank(A) =\left(\begin{matrix}7 & 0 & 0 \\0 & 7 & 0 \\0 & 0 & 7\end{matrix}\right)=3

3) The Rank (A) is 3 found through Gauss elimination

(A|B)=\begin{pmatrix}1 & -3 &-2  &6 \\  2& -4 &-3  &8 \\  -3&6  &8  &-5 \end{pmatrix}

rank(A|B)=\left(\begin{matrix}1 & -3 & -2 \\0 & 2 & 1 \\0 & 0 & \frac{7}{2}\end{matrix}\right)=3

4) The rank of (A|B) is also equal to 3, found through Gauss elimination:

So this linear system is consistent and has a unique solution.

8 0
3 years ago
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