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3 years ago

Is a dot matrix printer an impact or non-impact printer

Computers and Technology

2 answers:

IRISSAK [1]3 years ago

5 0

I think a non impact printer

asambeis [7]3 years ago

5 0

Answer:

Impact

Explanation:

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Please help with this:

Tanzania [10]

Answer:

I'm not gonna give you the answer. I want you to think about this what is math, what is science, how does it help the world, and etc. These are some example questions to help.

Explanation:

5 0

3 years ago

Write a program that produces this output:

AveGali [126]

Answer:

void printC()

{

int i, j;

for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows

{

printf("C"); //print C for every row

for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows

{

if (i == 0 || i == 4) //For first and last row

printf("C"); //print 'CCCCCCC'

else if (i = 1|| i= 3) //for Second forth row

printf("C + +"); //print 'C + +'

else if (i = 2) For second row

printf("C +++++"); //print 'C +++++'

else

continue; //to jump to next iteration

}

printf("\n"); // print in next line

}

4 0

3 years ago

What is the name of the nearest major galaxy to Milky-Way ?

nika2105 [10]

The Andromeda Galaxy would be my answer.

3 0

3 years ago

If an individual receives 1.8 mGy while standing 4 ft from a source of radiation for 2 minutes, which of the following option(s)

erastovalidia [21]

Answer:

The answer is letter B.

Explanation:

The option that will most effectively reduce her or his radiation exposure to that source is Standing 8 ft from the source for 2 minutes.

6 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago