Answer: Null hypothesis : 
Alternative hypothesis : 
Step-by-step explanation:
Let
be the proportion of women using supplements and
be the proportion of women who did not to have died during that period .
Then the set of hypothesis for testing if the proportion of women elderly women who use dietary supplements is different than those who do not will be :-
Null hypothesis :
[∵ it takes equality sign]
Alternative hypothesis :
[∵ it takes ≠ sign to show difference]
Answer:
D. 14.32
Step-by-step explanation:
The formula for standard deviation is:

The mean μ is 33.
The (x minus μ) squared are 361, 49, 49, 361 respectively.
So that the SD = 
F(x) = 3x + 9
g(x) = 5x²
(f + g)(x) = (3x + 9) + 5x²
(f + g)(x) = 3x + 9 + 5x²
(f + g)(x) = 5x² + 3x + 9
Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649