Answer:
Absolute value of a number is denoted by two vertical lines enclosing the number or expression. For example, the absolute value of number 5 is written as, |5| = 5. This mean that, distance from 0 is 5 units: Similarly, the absolute value of a negative 5 is denoted as, |-5| = 5.
Step-by-step explanation:
Answer:
<h2>-5</h2>
Step-by-step explanation:
Answer:155.2$
Step-by-step explanation:
She works 2 day in week 8 hour in each day so
8×2×9.70=155.2$
Answer:
<em>(B) Revenue account which increases
</em>
Step-by-step explanation:
Hello, my dear friend, I am sure the question you are intending should be corrected as follows:
In transaction (C) on 5/10, the Fees Earned account is a(n) A. Expense account, which increases B. Revenue account, which increases C. Revenue account, which decreases D. Asset account, which decreases
If that is the case, then please note that whatever amount you earn, is an amount that will always increase. If you have no earnings, then nothing decreases nor decreases.
Answer:
The factored expression is 2(x² + 5)(x + 3).
Step-by-step explanation:
Hey there!
We can use a factoring technique referred to as "grouping" to solve this problem.
Grouping is used for polynomials with four terms as a quick and easy factoring method to remove the GCF and get down to the initial terms that create the expression/function.
Grouping works in the following matter:
- Given equation: ax³ + bx² + cx + d
- Group a & b, c & d: (ax³ + bx²) + (cx + d)
- Pull GCFs and factors
Let's apply these steps to the given equation.
- Given equation: 2x³ + 6x² + 10x + 30
- Group a & b, c & d: (2x³ + 6x²) + (10x + 30)
- Pull GCFs and factors: 2x²(x + 3) + 10(x + 3)
As you'll see, we have a common term with both sides of the expression. This term, (x + 3), is a valuable asset to the factoring process. This is one of the factors for our expression.
Now, we use our GCFs to create another factor.
- List GCFs: 2x², 10
- Create a term: (2x² + 10)
Finally, we'll need to simplify this one by taking another GCF, 2.
- Pull GCF: 2(x² + 5)
Now that we have this term, we need to understand that this <em>could</em> also be factored further using imaginary numbers, but it is also acceptable to leave it in this form.
Therefore, we have our final factors: 2(x² + 5) and (x + 3).
However, when we factor, we place all of our terms together. This leaves us with the final answer: 2(x² + 5)(x + 3).