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dmitriy555 [2]
4 years ago
10

Whats the cube root of negative 125

Mathematics
1 answer:
Minchanka [31]4 years ago
8 0

If it is an odd number root of any negative number, the answer will be negative.

From this you can see that -5 x -5 x -5 = -125, so the asnwer is -5.

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Someone help me pleaseeee
motikmotik

Answer:

3,943.84

Step-by-step explanation:

Since we know the angle of the arc is 70°, its length will be 7/36 of the whole circumference. The circumference, which is 2*pi*r, is 20 pi = 62.8, so the arc JL is 7/36 * 62.8 = 3,943.84

3 0
2 years ago
60 ☐ (72 ☐ 12) ☐ 34 = 44 Use the operations: ÷, +, and -
julia-pushkina [17]

Answer:

its 60 / (72/12) + 34 = 44. So divide, divide, add.

Step-by-step explanation:

First, solve the what's in the parentheses. 72/12 = 6.

60/6 = 10.

34+10 = 44.

3 0
4 years ago
among the 2302 respondents, 1510 said that they only play hockey. What percentage of respondents said that they only play hockey
Irina18 [472]
1510 / 2302 = 0.6559 = 65.59%.....not sure if u need that rounded 
7 0
3 years ago
Can someone help me with this physics equation please I am really in need of help
e-lub [12.9K]

Answer:

The current is approximately 8.571 Amps

Step-by-step explanation:

You are supposed to use Ohm's Law for this problem.

Recall that Ohm's Law gives you the relationship between voltage applied (V), resistance (R) and current (I):  

V=I\,*\,R

If the units of resistance are ohms, and the voltage is in volts, the current will be given in Amps (amperes). Then solving for the current (I) in the above equation:

I=\frac{V}{R} \\I=\frac{120}{14} \\I=8.571\,\,Amps

3 0
4 years ago
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0
3 years ago
Read 2 more answers
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