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Butoxors [25]
3 years ago
10

Using the equation F = ma, find the acceleration (a) of a 15 kg mass (m) that is acted on by 3 Newtons of Force (F). Group of an

swer choices
Mathematics
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

a = 0.20 m/s²

Step-by-step explanation:

F = 3 N

m = 15 kg

F = m * a

find mass m:

3 = 15 * a

a = 3 / 15

a = 0.20 m/s²

Tcecarenko [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Yes

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Write 640 g as a fraction of 4.8 kg. Give your answer in its simplest form,
vitfil [10]

Answer:

Step-by-step explanation:

640g=640g

4.8kg=4800g

640g/4800g=2/15

7 0
2 years ago
Cuanto es 12x + 12 = 12 + 12
lukranit [14]

Answer:

12x + 12 = 12  + 12 \\ 12x = 12 \\ x = 1 \\  \\ x + 4x = x + 48 \\ 4x = 48 \\ x = 12 \\  \\ 3x + 12 = 24 - 5 + 2x - 1 \\ 3x - 2x = 24 - 12 - 5 - 1 \\ x = 6

8 0
3 years ago
State the degree and dominant term of this polynomial
artcher [175]

The degree of the polynomial f(x) = 2x(x - 3)³(x + 1)(4x - 2) is 6, and the dominant term is - 216x²

<h3>The degree of the polynomial?</h3>

The polynomial function is given as:

f(x) = 2x(x - 3)³(x + 1)(4x - 2)

To determine the degree, we simply add the multiplicities.

So, we have:

Degree = 1 + 3 + 1 + 1

Evaluate

Degree = 6

Hence, the degree of the polynomial is 6

<h3>The dominant term of the polynomial</h3>

We have:

f(x) = 2x(x - 3)³(x + 1)(4x - 2)

Expand

f(x) = 8x⁶ - 68x⁵ + 176x⁴ - 72x³ - 216x² + 108x

The term with the highest absolute value is - 216x²

Hence, the dominant term is - 216x²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
Answer all of the following questions. 3 Points a question. ALSO NO LINKS!
zubka84 [21]

Answer:

no

yes

yes

no

no

yes

Step-by-step explanation:

a prime number cant be devided by any thing other than itself or one

5 0
3 years ago
Solve by using elimtation
Wewaii [24]

Answer:

1. x = 5, y = 13/2

2. x = 15 , y = 24

Step-by-step explanation:

Solve the following system:

{8 y + 6 x = 82 | (equation 1)

{6 y + 9 x = 84 | (equation 2)

Swap equation 1 with equation 2:

{9 x + 6 y = 84 | (equation 1)

{6 x + 8 y = 82 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{9 x + 6 y = 84 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 1 by 3:

{3 x + 2 y = 28 | (equation 1)

{0 x + 4 y = 26 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + 2 y = 13 | (equation 2)

Divide equation 2 by 2:

{3 x + 2 y = 28 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x + 0 y = 15 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 5 | (equation 1)

{0 x + y = 13/2 | (equation 2)

Collect results:

Answer: {x = 5, y = 13/2

_____________________________________

Solve the following system:

{8 y + 3 x = 237 | (equation 1)

{3 y + 5 x = 147 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = 147 | (equation 1)

{3 x + 8 y = 237 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = 147 | (equation 1)

{0 x + (31 y)/5 = 744/5 | (equation 2)

Multiply equation 2 by 5/31:

{5 x + 3 y = 147 | (equation 1)

{0 x + y = 24 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x + 0 y = 75 | (equation 1)

{0 x + y = 24 | (equation 2)

Divide equation 1 by 5:

{x + 0 y = 15 | (equation 1)

{0 x + y = 24 | (equation 2)

Collect results:

Answer: {x = 15 , y = 24

3 0
2 years ago
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