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pentagon [3]
3 years ago
6

5. Evaluate the quadratic function f(x) = 5(x-3)(x-2) when x = 9​

Mathematics
2 answers:
tatyana61 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

f(9)=5(9-3)(9-2)

=5*6*7

=210

S_A_V [24]3 years ago
5 0

Answer:

f(9) = 210

Step-by-step explanation:

In f(x) = 5(x-3)(x-2), replace each instance of x with 9:

f(9) = 5(9-3)(9-2), or:

       =5(6)(7) = 210

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Marianna [84]
30 + 70 + D = 180
100 + D = 180
D = 80°
7 0
2 years ago
1. Is g = 2 a solution (the correct<br> answer) to 3g = 6? PROVE why or why<br> not.
kherson [118]

Answer:

yes this is true

Step-by-step explanation:

this is because 2x3=6 so 2x3g=6g

4 0
3 years ago
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
A car's velocity is modeled by
Igoryamba

In accordance with the function <em>velocity</em>, the car will have a complete stop after 6 seconds.

<h3>When does the car stop?</h3>

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the <em>quadratic</em> formula we get the following two roots: t₁ = 15, t₂ = 6. The <em>stopping</em> time is the <em>least</em> root of the <em>quadratic</em> equation, that is, the car will have a complete stop after 6 seconds.

To learn more on quadratic equations: brainly.com/question/2263981

#SPJ1

8 0
1 year ago
Which statements are true about the interquartile range? Select all that apply.
PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

  • Put the numbers in order
  • Find the median Place parentheses around the numbers before and after the median
  • Find Q1 and Q3 which are the medians of the data before and after the median of all data
  • Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>

<em />

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>

<em />

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)

E. The data values should be listed in order before trying to find the interquartile range  ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>

4 0
3 years ago
Read 2 more answers
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