Is this non-linear? If not, what’s the rate of change? Please show your work, I’m kind of confused.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

7 0

It is non-linear, you can tell because it’s not evenly proportional, -2 to 0 is +2, but 0 + 2 is 2

You might be interested in

How much sit-ups can you do in 1 minutes?

galben [10]

I can do like 42, my highest was 54 though

8 0

3 years ago

Find the the slope of the line passing through points 2,2 and -1,0

scZoUnD [109]

For a given function, slope is defined as the change in outputs, or y-values divided by the change in inputs, or x-values. In essence the slope asks "For a given change in x, how much does y change?" or even more simply: "How steep is the graph of this function?". This can be represented mathematically by the formula: $slope=m=\frac{rise}{run}=\frac{\Delta y}{\Delta x}-\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting our known vlaues we have:
$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m=\frac{2-0}{2-(-1)}$
$m=\frac{2}{3}$

7 0

3 years ago

If 1 - cosA= 1/2 show that tan²A + 4sin²A = 6

pav-90 [236]

$\text{Given that,}\\\\1-\cos A = \dfrac 12\implies \cos A = 1-\dfrac 12 = \dfrac 12\\\\\text{L.H.S}\\\\=\tan^2 A + 4 \sin^2 A\\\\=\dfrac{\sin^2 A}{\cos^2 A}+4(1-\cos^2 A)\\\\\\=\dfrac{1-\cos^2 A}{\cos^2 A} +4-4\cos^2 A\\\\\\=\dfrac{1-\left( \dfrac 12 \right)^2 }{\left(\dfrac 12 \right)^2 } +4 -4 \left( \dfrac 12 \right)^2\\\\\\=\dfrac{1- \dfrac 14}{\dfrac 14}+4-4\cdot \dfrac 14\\\\\\=\dfrac{\tfrac 34}{\tfrac 14}+4-1\\\\\\=\dfrac 34 \cdot 4 +3\\\\=3+3\\\\=6\\\\=\text{R.H.S}$