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VashaNatasha [74]
3 years ago
13

Solve 15 = 1/3x what is the value of x

Mathematics
1 answer:
choli [55]3 years ago
7 0

the value of x is x=5

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babymother [125]
I'm sorry ninth grade slow learner


4 0
3 years ago
A corporate bond has a coupon rate of 5.5 percent, a $1,000 face value, and matures three years from today. The corporation is i
melomori [17]

Answer:

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

Step-by-step explanation:

= (probability of entire face value paid*face value+probability of entire face value not paid*percent of face value paid*face value)/(1+discount rate)^years to maturity

probability of entire face value paid = 75%

face value = 1000

probability of entire face value not paid = 25%

percent of face value paid= 60%

discount rate = 15%

years to maturity  = 3

= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000  }{(1+\frac{15}{100})^3 }

=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}

=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76

6 0
2 years ago
What is y=\dfrac{2}{3}x+4y=
lara [203]

Answer:

12y+x-12=0

Step-by-step explanation:

If I'm not mistaken by the question, we have

x+4y=\dfrac{2}{3}x+4

Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)

3\timesx+3\times4y=3\times\dfrac{2}{3}x+3\times4

3x+12y=2x+12

Putting all terms on the LHS (left hand side) and evaluating,

12y+x-12=0

5 0
3 years ago
If the independent variable becomes very large what would be the expected change in the dependent variable
jenyasd209 [6]

Answer: The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

Step-by-step explanation:

5 0
3 years ago
What is the interquartile range of this data? A.6 B.7 C.8 D.9
Butoxors [25]
Hello!

To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile. 

33 - 25 = 8

The interquartile range is 8. Hope I helped! :3
6 0
3 years ago
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