Solve 15 = 1/3x <br>what is the value of x

Ed works 5.8 hours each day ,if ed make 8$ per hour how much will he ear in 60 days

Nina [5.8K]

Answer: he will make $2784 in 60 days

5 0

3 years ago

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A sentence must contain an adjective to be a complete sentence??? True or false

pashok25 [27]

False because the sentence can be completed well without adjective too

4 0

4 years ago

Jacqueline reach the end of the trail in two hours and 15 minutes. Write the amount of hours he spent on the trail as a mixed nu

LenaWriter [7]

You would keep the 2 hour for the whole number of the mixed number and then, make the minutes (15) as a fraction with 60, and divide them both by 20. that is just for the mixed number.

4 0

4 years ago

Find the length and width of a rectangle.<br> Perimeter = 50<br> Side A = 3x + 2<br> Side B = x - 5

zmey [24]

Step-by-step explanation:

Perimeter = 2 * (Side A + Side B)

= 2 * (3x + 2 + x - 5)

= 2 * (4x - 3)

= 8x - 6.

We have 8x - 6 = 50, so 8x = 56 and x = 7.

Length of rectangle = 3(7) + 2 = 23.

Width of rectangle = (7) - 5 = 2.

4 0

3 years ago

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What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

4 years ago

Solve 15 = 1/3x what is the value of x