For no real solution, you must have b^2 - 4ac of the quadratic formula be less than 0.
a = 1; b = 2; c = C
b^2 - 4ac < 0
2^2 - 4(1)(C) < 0
4 - 4C < 0
-4C < -4
C > 1
The only choice greater than 1 is 3.
Answer: the 4th choice, 3
Answer:
Step-by-step explanation:
(x-2)/2 = -3
x - 2 = -6
x = -4
(y + 2)/2 =4
y + 2 =8
y = 6
(-4, 6)
(x^2 + 4x + 8)(2x - 1) = 2x(x^2 + 4x + 8) - (x^2 + 4x + 8) = 2x^3 + 8x^2 + 16x - x^2 - 4x - 8 = 2x^3 + 7x^2 + 12x - 8
Answer:
1/64
Step-by-step explanation:
There are 8 equal sections
P(1) = 1/8 since there is one section with a 1 out of the 8 sections
Then we spin again
P(2) = 1/8 since there is one section with a 2 out of the 8 sections
P(1, then 2) = P(1) * P(2) since they are independent events
= 1/8 * 1/8
= 1/64
Answer:
x=6
Step-by-step explanation:
5x+4+8x-3=79
=>13x=79-4+3
=>13x=78
=>x=78/13
=>x=6
