What is the solution to the following system? (picture)

What pair of fractions is 0.8 between on a number line

madam [21]

0.8 has one decimal.. so... let's make it a fraction first, by using one zero with a one as denominator.

$\bf 0.\underline{8}\implies \cfrac{08}{1\underline{0}}\impliedby \textit{one decimal, one zero, no dot}
\\\\\\
\cfrac{8}{10}\implies \cfrac{4}{5}
\qquad \qquad \qquad 
......\cfrac{1}{5}..\cfrac{2}{5}..\cfrac{3}{5}..\boxed{\cfrac{4}{5}}..\cfrac{5}{5}..\cfrac{6}{5}..\cfrac{7}{5}......$

is between any of those, among many other fractions as well.

3 0

3 years ago

WILL GIVE BRAINLIEST!!!!!!!

lara [203]

Paralell has same slope
slope of ax+by=c is -a/b
so a paralalell line to ax+by=c is ax+by=z where a=a and b=b and z is a constant

so
paralalel to 3x-2y=-6 is 3x-2y=?
find ?
given point (4,2)
sub
3(4)-2(2)=12-4=8

equation is 3x-2y=8
solving for slope itnercept or y
minus 3x both sides
-2y=-3x+8
divide by -2
y=3/2x-4

B is answer

8 0

3 years ago

1032555555+777777877852532000=?

igor_vitrenko [27]

Answer:

777777878885087555

or

7.77777878 * 10^17

Step-by-step explanation:

5 0

3 years ago

The gear is one of the oldest mechanical devices. It has been used since ancient times for its ability to increase or decrease r

eduard

The large gear attached to the pedals connected to the smaller gear

attached to the wheel allows the bicycle to travel further per rotation.

Correct responses:

Part A: Approximately 10.47 inches

Part B: 300°The d

Part C: Approximately 125.66 inches

Part D: The distance traveled increases by approximately 62.83 inches

<h3 /><h3>Methods used to calculate the above values</h3>

Given:

The radius of the large central gear, <em>r</em> = 4 inches

Radius of the small gear = 2 inches

Part A:

The distance travelled by the larger gear when the angle of rotation is 150° is given as follows;

$\displaystyle Distance \ travelled \ by \ larger \ gear = \mathbf{\frac{150^{\circ}}{360^{\circ}} \times 2 \times \pi \times 4 \, inches} = \frac{10}{3} \cdot \pi \ inches$

$\displaystyle Distance \ traveled \ by \ the \ outer \ edge = \frac{10}{3} \cdot \pi \ inches \approx \underline{ 10.47 \ inches}$

Part B:

When the small gear travels the same linear distance as the large gear in part A, we have;

$\displaystyle Degree \ of \ rotation = \frac{\frac{10}{3} \cdot \pi }{2 \times \pi \times 2 } \times 360^{\circ}= 300^{\circ}$

The degree of rotation of the small gear = <u>300°</u>

Part C:

The distance travelled, <em>C</em>, by a single rotation of the large gear is given as follows;

C = 2 × π × 4 inches = 8·π inches

The degree of rotation of the smaller gear following one rotation of the large gear is therefore;

$Degree \ of \ rotation = \displaystyle \frac{8\cdot \pi \ inches}{4 \cdot \pi \ inches } \times 360^{\circ} = \mathbf{ 720^{\circ}}$

720° = 2 × 360°

1 complete rotation is equivalent to 360°.

Therefore'

720° is equivalent to two complete rotation.

Therefore, the smaller gear and the wheel rotates twice for each rotation of the large gear

The distance the bicycle travels = 2 × The circumference of the wheel

Therefore;

Distance traveled by the bicycle = 2 × 2 × π × 10 inches = 40·π inches

Distance traveled by the bicycle = 40·π inches ≈ <u>125.66 inches</u>

Part D:

If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;

Number of rotation of the small gear for each rotation of the large gear = 3 rotations

Therefore, number of rotation of the wheel = 3

Distance the bicycle travels = 3 × 2 × π × 10 inches = 60·π inches

The difference in distance traveled = 60·π inches - 40·π inches = 20·π inches

The distance traveled by the bicycle increases by 20·π inches ≈ <u>62.83 inches</u>

Learn more about gear transmission here:

brainly.com/question/14646065

brainly.com/question/3926797

8 0

3 years ago

ANSWER THIS CORRECTLY FOR BRAINLIEST!!!!<br><br> This is 8th grade<br> algebra btw

gulaghasi [49]

Answer:

V = 2143.57

Step-by-step explanation:

To find the volume of a sphere you need to use this formula:

$V = \frac{4}{3}\pi r^{3}$

r = radius

Solve:

You need the radius from the diameter. Divide 16/2 which is

8.

$V = \frac{4}{3}(3.14) 8^{3}$

V = 2143.57

7 0

2 years ago

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