1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paul [167]
3 years ago
6

What is the solution to the following system? (picture)

Mathematics
1 answer:
adoni [48]3 years ago
7 0

option C

PLS MAKE ME AS THE BRAINLIEST ANSWER

You might be interested in
Need help not sure what to do
Rama09 [41]

5a)

2x + 94 = 7x + 49 (vertical angles are equal)

2x - 7x = -94 + 49

-5x = -45

x = 9

Answer

9

5b)

4y + 7x + 49 = 180 (supplementary angles, sum = 180)

4y + 7(9) + 49 = 180

4y + 112 = 180

4y = 68

y = 17

Answer

17

6)

x = 6x - 290 (vertical angles are equal)

-5x = -290

  x = 58

Answer

58


7 0
3 years ago
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
Factor completely<br> x^4 -81
PtichkaEL [24]
x^4-81=\\&#10;(x^2-9)(x^2+9)=\\&#10;(x-3)(x+3)(x^2+9)&#10;
4 0
4 years ago
If sin = 3/5 and 0 &lt;= x &lt;= pi/2 , find the exact value of tan 2θ.
Alexxandr [17]

For starters,

tan(2θ) = sin(2θ) / cos(2θ)

and we can expand the sine and cosine using the double angle formulas,

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = 1 - 2sin^2(θ)

To find sin(2θ), use the Pythagorean identity to compute cos(θ). With θ between 0 and π/2, we know cos(θ) > 0, so

cos^2(θ) + sin^2(θ) = 1

==>  cos(θ) = √(1 - sin^2(θ)) = 4/5

We already know sin(θ), so we can plug everything in:

sin(2θ) = 2 * 3/5 * 4/5 = 24/25

cos(2θ) = 1 - 2 * (3/5)^2 = 7/25

==>  tan(2θ) = (24/25) / (7/25) = 24/7

6 0
4 years ago
1 The legs of a triangle are 6 cm and 8 cm. The hypotenuse is 14 cm. Is it a right triangle?
Vitek1552 [10]

Answer:

this is not a right triangle

Step-by-step explanation:

^  = squared

The formula forthe Pythagorean theorem is    a^+ b^   = c^

If this is a right triangle this must be true

6^ +    8^   =   14^

36 + 64 =  196

100  is not equal to 196

So this is not a right triangle

3 0
3 years ago
Other questions:
  • How do you multiply this?? Explain please!!!!
    7·1 answer
  • What is the acceleration, in meters per second squared, of a 2,000,000-kilogram NASA rocket with an applied force of 20,000,000
    7·1 answer
  • Write 130% as a fraction in lowest terms.
    10·2 answers
  • Katrina and her family received 147 pieces of chocolate packed in boxes of 21. Her family ate 3 boxes of chocolate. How many box
    14·2 answers
  • Solve for X
    8·1 answer
  • SIMPLE SEVENTH GRADE MATH PROBLEM, GIVING BRAINLIEST.
    15·2 answers
  • You and your family are driving to the Wild Animal Park in Escondido, CA. The distance from your house to the park is 528 miles.
    12·1 answer
  • Using only addition what is 20 - 9 + 8 -7
    12·2 answers
  • What is the ratio and diameter of the following Circle 4.2 cm ​
    13·1 answer
  • Write the equation of the line perpendicular to y = 3/5×+4/5 that passes through the point (-6,2).
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!