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Paul [167]
3 years ago
6

What is the solution to the following system? (picture)

Mathematics
1 answer:
adoni [48]3 years ago
7 0

option C

PLS MAKE ME AS THE BRAINLIEST ANSWER

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The surface areas of two similar solids are 416yd ^2 and 1,354yd ^2. The volume of the larger solid is 2,976 yd^3. What is the v
KatRina [158]
I believe the correct answer is 914 yd ^3hope this helps!

8 0
3 years ago
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There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there
vodomira [7]

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.  

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}

Thus there will be 1.078x students in next year

3 0
3 years ago
Help with question 4 please
musickatia [10]

Answer:

dont know

Step-by-step explanation:

sorry

6 0
3 years ago
A six-week fitness program was designed to decrease the time it takes retired individuals to walk one mile. At the beginning of
valkas [14]

Answer:

c. The sampling distribution of the sample means can be assumed to be approximately normal because the distribution of the sample data is not skewed

Step-by-step explanation:

From the given data, we have;

The category of the sample = Retired individuals

The number of participants in the sample = 20

The duration of program = six-weeks

The improvement seen by most participants = Little to no improvement

The improvement seen by few participants = Drastic improvement

Therefore, given that the participants are randomly selected and the majority of the participants make the same observation of improvement in the time to walk a mile, we have that, the majority of the outcomes show little difference in walk times after the program, therefore, the distribution of the sample data is not skewed and can be assumed to be approximately normal

7 0
3 years ago
Need some help pleas
FromTheMoon [43]

Answer:

80%

Step-by-step explanation:

If you divide 52 by 65 you will get a decimal, then multiply by 100% to get the equivalent.

52/65 = 0.8

0.8 x 100 = 80%

4 0
3 years ago
Read 2 more answers
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