To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
What in the world is that
Answer:
4x=y
Step-by-step explanation:
4x=y is your answer because if x is 5, like in the table, then 4(5) would equal 20, which is the y-value. It also works for every number in the table.
Hope this helps.
Yes for the first and last the middle one should also be x^2+4