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2 years ago

A null hypothesis is being tested. How does the confidence level affect the testing process?

1 answer:

5 0

If you have a high confidence level, the chance of rejecting the null hypothesis is rare. If you have a low confidence level, the chance of of rejecting the null hypothesis is nonexistent. If you have a low confidence level, the chance of of rejecting the null hypothesis is rare. If you have a high confidence level, the chance of of rejecting the null hypothesis is high.

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A circle has an area of 25pi Find the radius of the circle. A. 5 B. 10 C. 25

EastWind [94]

Answer:

A. 5

Step-by-step explanation:

Given the area of the circle is 25pi. We will divide by pi. Then, the radius of the circle is r= 5.

4 0

2 years ago

Read 2 more answers

PLEASE HELP!!! WILL GIVE BRAINLIEST!!!

777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

$y=x^2+x-4\\y=-2x+6$

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

$x^2+x-4=-2x+6$

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

$x^2+x-4+2x-6=0$ Finish things here (Subtract and Addition)

$x^2+3x-10=0$ What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

$(x-2)(x+5)=0$ (5-2 = 3) and (5*(-2) = -10)

Then we get both x, $x=2,-5$

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

$y=-2(2)+6\\y=-4+6\\y=2$

Order = $(2,2)$

Then substitute x = -5 in y=-2x+6

$y=-2(-5)+6\\y=10+6\\y=16$

Order = $(-5,16)$

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0

3 years ago

7. The terminal side of theta, and angle in standard position, intersects the unit circle at

SIZIF [17.4K]

Complete question is;

The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?

Answer:

csc θ = -13/12

Step-by-step explanation:

We know that in a unit circle;

(x, y) = (cos θ, sin θ)

Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;

cos θ = -10/26

sin θ = -24/26

Now we want to find csc θ.

From trigonometric ratios, csc θ = 1/sin θ

Thus;

csc θ = 1/(-24/26)

csc θ = -26/24

csc θ = -13/12

7 0

2 years ago

I need so much help please somebody help me

marysya [2.9K]

Answer:

$448

Step-by-step explanation:

You need to find 2% of 400.00, so you would do this: 0.02 · 400 = 8

That means $8 is 2% of 400, so all you need to do is multiply 8 by 6 to get 48. Add that number to the original $400, and you get $448.

Hope this answers your question!

6 0

2 years ago

Help me please !! give me right answer .

harina [27]

Answer:

2.04

Step-by-step explanation:

4 0

2 years ago