Answer:
And....what are the options? or are we suppose to know answer that?
Will lets say box one is red (r), box two is green(g), Box three is blue(b) and box four is yellow(y). If you have 10 tennis balls then 2 tennis balls in the Red Box, 2 tennis balls in the green box, 2 tennis balls in the blue box and 2 tennis balls in the yellow box now you should have two left over so but one in the Red box and the other in the Blue box! I don't know if this is right but I am a little confused on what your saying so Hope this helps:)
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Answer:
a) Minimize
subject to
b) Attached
c) The optimum value that minimizes cost is x1=28 and x2=8.
Step-by-step explanation:
The objective function is the cost of extraction and needs to be minimized.
The cost of extraction is the sum of the cost of extraction of ore type 1 and the cost of extraction of ore type 2:
Being x1 the tons of ore type 1 extracted and x2 the tons of ore type 2.
The constraints are the amount of minerals that need to be in the final mix
Copper:
Zinc
Magnesium
Of course, x1 and x2 has to be positive numbers.
The feasible region can be seen in the attached graph.
The orange line is the magnesium constraint. The red line is the copper constraint. The green line is the zinc constraint.
The optimal solution is found in one of the intersection points between two constraints that belong to the limits of the feasible region.
In this case, the cost can be calculated for the 3 points that satisfies the conditions.
The optimum value that minimizes cost is x1=28 and x2=8.
Answer:
Step-by-step explanation:
Generally equation of a line is given as
y=mx+c
Then given the point (x, y)=(0,2)
Therefore x=0 and y=2
y=mx+c
2=m×0+c
2=0+c
Then, c=2
Then intercept is 2
Also given the point (x, y)=(3,4)
x=3 and y=4 and c=2
y=mx+c
4=m×3+2
4=3m+2
4-2=3m
2=3m
Then, m=2/3
Then, the slope of the graph is 2/3
y=mx+c
Now, m=2/3 and c=2
The general equation of the line becomes
y=2/3x+2
Multiply through by 3
3y=2x+6
Then this is the equation of the line
Answer:
Solution given
side 1:1 units
side 2=4 units
height =3 units
we have
Area of trapezoid =½*height(side1+side2)
=½*3(1+4)=15/2
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