Where’s the rest of the question? if there was more to the question i could assist you.
Answer:
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Explanation:
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Answer:
Convection
Explanation:
I hope it helps Let me know.
The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
![SE = \frac{\sigma}{\sqrt n}](https://tex.z-dn.net/?f=SE%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D)
The standard error of the Canadian sample is:
![SE_1 = \frac{2.9}{\sqrt{50}}](https://tex.z-dn.net/?f=SE_1%20%3D%20%5Cfrac%7B2.9%7D%7B%5Csqrt%7B50%7D%7D)
So, we have:
![SE_1 = 0.41](https://tex.z-dn.net/?f=SE_1%20%3D%200.41)
The standard error of the American sample is:
![SE_2 = \frac{1.3}{\sqrt{60}}](https://tex.z-dn.net/?f=SE_2%20%3D%20%5Cfrac%7B1.3%7D%7B%5Csqrt%7B60%7D%7D)
So, we have:
![SE_2 = 0.17](https://tex.z-dn.net/?f=SE_2%20%3D%200.17)
The standard error of the difference of sample means is then calculated as:
![SE= \sqrt{SE_1^2 + SE_2^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7BSE_1%5E2%20%2B%20SE_2%5E2%7D)
This gives
![SE= \sqrt{0.41^2 + 0.17^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.41%5E2%20%2B%200.17%5E2%7D)
![SE= \sqrt{0.197}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.197%7D)
Take square roots
![SE= 0.444](https://tex.z-dn.net/?f=SE%3D%200.444)
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at:
brainly.com/question/6851971