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3 years ago

An escalator lifts people to the second floor of a building, 28 ft

Mathematics

1 answer:

Marysya12 [62]3 years ago

4 0

9514 1404 393

Answer:

56 ft

Step-by-step explanation:

The geometry can be modeled by a right triangle with an unknown hypotenuse, and a side opposite the 30° angle that is 28 ft.

sin(30°) = (28 ft)/hypotenuse

hypotenuse = (28 ft)/sin(30°) = 56 ft

The length of the escalator is 56 feet.

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Write the Slope- Intercept equation of the line that passes through the given point and is perpendicular to the given line (0, -

damaskus [11]

Answer:

y+4=-3(x+0) or y=-3x-4

Step-by-step explanation:

so you have to make it in form y=mx+b

that would be y=1/3x-2/3

for a perpendicular line, you would need to find the opposite reciprocal of the slope

3/1 or 3 would be the reciprocal, so to make it opposite would be -3

So it would be y-y1 = m(x-x2)

fill it in with the coordinates (0,-4)

y+4=-3(x-0)

to get it to slope intercept form you have to simplify, and after that you get y=-3x-4

4 0

3 years ago

Find the domain and the range of the relation. Determine whether the relation is a function.

andre [41]

Answer:

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

The relation is not a function.

Step-by-step explanation:

Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}

In the ordered pairs:

The domain is the set of all "x" values
The range is set of all "y" values
We do not need to list any repeated value in the range/domain more than once.

Domain: {-6, -1, 7}

Range: {-9, 0, 9}

Next, we determine whether the relation is a function.

For a relation to be a function, each x must correspond with only one y value.

However, as is observed in the mapping attached below:

f(-1)=0
f(-1)=9

The x-value (-1) corresponds to two y-values (0 and 9)

Therefore, the relation is not a function.

8 0

3 years ago

Z is..? The problem is attached as a png!

VikaD [51]

Answer:

Step-by-step explanation:

What i would do is multiply both sides by 2z + 1

so you get z-6=20z+10

-19z=16

z=-16/19

5 0

3 years ago

Read 2 more answers

Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v

Juliette [100K]

Compute the surface element:

$\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv$

$\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}$

$\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}$

So the integral is

$\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$

$=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)$

$=\dfrac23(37^{3/2}-1)$

4 0

3 years ago

I don't understand! help please!!!

Lina20 [59]

Answer:

try leaving and coming back to it

Step-by-step explanation:

7 0

3 years ago