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3 years ago

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Danny’s 7 friends contributed an equal amount of money to buy him a birthday present. The present cost $84. How much money do ea

ch friend contribute?

1 answer:

SOVA2 [1]3 years ago

7 0

The answer would be 12 dollars. you divide 84 by 7 and you end up with 12.

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Plz help! I need at least 2 answers

klemol [59]

Answer:

I can't see the side lengths so I can't answer it

Step-by-step explanation:

7 0

3 years ago

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The Loft Theater has a center seating section with 3c + 8 rows and 4c-1 seats in each row. Write an expression for the total num

yulyashka [42]

If there are n rows

And if each row has m seats.

Then the total number of seats shall be n × m.

Here

Number of rows = (c+8)

And number of seats in each row = (4c-1)

Using the concept

Total number of seats

= (c+8)(4c-1)

FOILing or Distributing we get

= c(4c) + c (-1) + 8(4c) +8 (-1)

= 4c² - c + 32 c -8

Combining like terms

=4c² +31c - 8

The expression for total number of seats = 4c² + 31c -8

4 0

3 years ago

Three friends went to the movies. They shared a popcorn and a pack of

faust18 [17]

Answer:

Step-by-step explanation:

A) x+9 =45

x=45 - 9

x=36 cost the tickets

B) 36 :3=12 $cost a ticket

3 0

4 years ago

Find the indicator real nth root

ankoles [38]

It can be useful to know the prime factorization of the number:

$256 = 2^8$

Then, remember that the n-th root of a number is the same as that number to the 1/n-th power:

$\sqrt[4]{256} = 256^{\frac{1}{4}}$

Finally, you have to remember the rule for raising a power to another power, i.e. you multiply the exponents:

$(a^b)^c = a^{bc}$

Put together everything we said so far to write

$\sqrt[4]{256} = 256^{\frac{1}{4}} = (2^8)^{\frac{1}{4}} = 2^{\frac{8}{4}} = 2^2 = 4$

3 0

3 years ago

A circle with a radius of 1/2 ft is dilated by a scale factor of 8. Which statements about the new circle are true? Check all th

AfilCa [17]

The circle is being dilated by a factor of 8 so the radius will be 8 times the original radius (4 ft).

The circumference of a circle = $2\pi r$ , so if r is replaced by $8r$ we get $C = 2\pi * 8r$ or just $C = 8*(2\pi r)$ .

Basically the circumference will be 8 times the original circumference.

If you plug in the original radius, into this new formula you get $C_{new} = 8*(2\pi * \frac{1}{2}) = 8\pi \: ft$

The area of a circle = $\pi r^2$ , so if r is replaced by $8r$ we get $A = \pi*(8r)^2$ or just $A = 64\pi r^2$

Basically the area will be 64 times the original area.

If you plug in the original radius into this new formula you get $A = 64\pi * (\frac{1}{2})^2 = 16\pi \: ft^2$

The answers are A, C, F, G, and H

8 0

3 years ago

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