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777dan777 [17]
3 years ago
9

Triangle EFG is congruent to triangle YXZ by ASA. The congruent parts already marked in the picture. What other corresponding pa

rts can be marked congruent by CPCTC? Select all that apply.
EG ≅ YX
∠F ≅ ∠X
∠E ≅ ∠G
∠F ≅ ∠Z
∠G ≅ ∠X
GF ≅ ZX
EF ≅ YX
EF ≅ ZY

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

Given:

Triangle EFG is congruent to triangle YXZ by ASA.

To find:

The other corresponding parts can be marked congruent by CPCTC.

Solution:

We have,

\Delta EFG\cong \Delta YXZ

We know that the corresponding parts of congruent triangles are congregant (CPCTC). So,

\angle E\cong \angle Y

\angle F\cong \angle X

\angle G\cong \angle Z

EF\cong YX, it is also written as FE\cong XY

FG\cong XZ, it is also written as GF\cong ZX

EG\cong YZ, it is also written as GE\cong ZY

Therefore, the correct options are 2, 6 and 7.

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alina1380 [7]
Yes. 96 FL Oz is greater than 8 pt
3 0
3 years ago
Read 2 more answers
LOOK HOW MANY POINTS!!! PLEASE HELP ASAP A cell phone company tests 75 cell phones and finds that 3 of them have defects. Out of
kozerog [31]

Answer:

Out of 450 phones 18 of them will have a defect.

Step-by-step explanation:

As we know that out of 75 phones 3 of them will have a defect, this means that we are able to calculate how many defects there will be from 450 phones. You can do this by first dividing 450 by 75, this gives you 6. This means that 75 will go into 450 6 times.

From this we are able to work out the number that will have defects. This is because we know that 75 goes into 450 6 times and that for each 75 phones there will be 3 defects. So to work out the number of phones out of 450 that would be defects you would simply multiply 3 by 6, this gives you 18. This shows that out of 450 phones 18 of them will have a defect.

1) Divide 450 by 75.

450/75=6

2) Multiply 6 by 3.

6*3=18

3 0
4 years ago
Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be
Rina8888 [55]
This is a combination problem.

Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.

The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.

This is the formula I used because the order is not important and repetition is not allowed. 

Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.

numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960

Combination = 39,916,800 / 120,960 = 330

There are 330 ways that the instructor can choose 4 students for the first group


8 0
3 years ago
Read 2 more answers
Can someone please help?
liq [111]

Answer:

f(x) = (x + 4)^2 - 5

Step-by-step explanation:

Parent function: f(x) = x^2

To show this in a way that may look more familiar, f(x) = 1(x - 0)^2 + 0

Vertex form: f(x) = a(x - h)^2 + k

We know a = 1, because the slope is the same as the parent function.

Vertex: (h,k)

We can see that the vertex of the graph is (-4, -5)

So h = -4 and k = -5

Now all we need to do is plug the variables into our equation.

f(x) = a(x - h)^2 + k

f(x) = 1(x + 4)^2 - 5

f(x) = (x + 4)^2 - 5

5 0
3 years ago
A microwaveable cup-of-soup package needs to be constructed in the shape of cylinder to hold 350 cubic
const2013 [10]

Answer:

x = r = 3,12 cm

h = 11,45 cm

C(min) = 10,09 $

Step-by-step explanation:

Let x be radius of base  and  h height of cylinder

Let A₁ be   Cylinder area of base  +  lateral area

A₁  =  π*x²  +  2*π*x*h        Now V = 350 cm³     350  = π*x²*h

h = 350/ π*x²

Then

A₁  =  π*x²  +  700/x

A₂  area of the top

A₂  = π*x²

Now we write the expression of cost as fuction of x

C(x)  = 0,03 * ( π*x²  +  700/x)   +  0,08*π*x²

C(x)  = 0,03* π*x²  +   21/x   +  0,08*π*x²

C(x)  = 0,11* π*x² +   21/x  

Taking derivatives on both sides of the equation

C´(x)  =  2*0,11*π*x  - 21 / x²

C´(x)  = 0         0,22*π*x  - 21 / x²   =  0

0,22*π*x³  -  21  =  0         0.6908* x³  -  21   = 0

X³ =  21/0,6908               X³ =  30,40

x  =  3,12 cm

And

h  =  350/π*x²        h  =  350 / 30,57        

h = 11,45 cm

C(min)  =  0,11* π*(3,12)² +   21/3,12  

C(min)  =  3,36  + 6,73

7 0
4 years ago
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