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nikdorinn [45]
2 years ago
14

Find the first five terms of the sequence in which a = 3 and an = 2an - 1 + 13, if n 2 2.

Mathematics
1 answer:
Nina [5.8K]2 years ago
6 0
The answer to this question is D
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How many inches is 11.6 cm
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5 0
3 years ago
Evaluate the following expression (2.3)-3(1,1)
uranmaximum [27]

Answer:

<em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u> </u></em>

Step-by-step explanation:

1) Simplify  3 × (1, 1) 3 × (1, 1)  to  3× 1, 13 × 1,1.

<em>2</em><em>.</em><em>3</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>1</em><em>,</em><em> </em><em>1</em><em> </em><em>)</em>

2) Simplify 3 × 1 to 3.

2.3 - ( 3, 1)

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>3</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>3</u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>)</u></em><em><u>.</u></em>

3 0
3 years ago
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I need help please help me thanks please
Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})

\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright  y = 4x+(-1)\blacktriangleleft

4 0
3 years ago
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