Ignore this “answer” i just need to be able to ask more questions
You first have to turn 2x + 4y = -8 into y = mx + b before graphing. To do this, you subtract 2x from the left side of the equation because inverse operations. This will bring 2x to the right side. Now, you will have 4 = -2x + 8. However, you cannot have a number with y. Therefore, you must divide -8 and 2 by 4. You will get y = -1/2 x + 2 as your equation.
To graph -1/2x + 2, you must remember rise/run. Since it is NEGATIVE -1/2, your slope will go downwards (1 down, 2 across) starting from y = 2.
Answer: Choose 2 to the 4th power, 4 to the 2nd power, and 16 to the power of 1
Step-by-step explanation:
When working with exponents, whatever number is the corner of another number, multiply it by itself. For instance, if you have 2 to the 4th power, multiply 2x2x2x2 which is 16. Also there is 4 to the 2nd power which is 4x4 which is also 16. Lastly you have 16 to the power of 1 and anything multiplied by 1 stays the same.
You're given that φ is an angle that terminates in the third quadrant (III). This means that both cos(φ) and sin(φ), and thus sec(φ) and csc(φ), are negative.
Recall the Pythagorean identity,
cos²(φ) + sin²(φ) = 1
Multiply the equation uniformly by 1/cos²(φ),
cos²(φ)/cos²(φ) + sin²(φ)/cos²(φ) = 1/cos²(φ)
1 + tan²(φ) = sec²(φ)
Solve for sec(φ) :
sec(φ) = - √(1 + tan²(φ))
Given that cot(φ) = 1/4, we have tan(φ) = 1/cot(φ) = 1/(1/4) = 4. Then
sec(φ) = - √(1 + 4²) = -√17