Given:
PQRS is a circle, PQT and SRT are straight lines.
To find:
The value of x.
Solution:
Since PQRS is a circle, PQT and SRT are straight lines, therefore, PQRS isa cyclic quadrilateral.
We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.




Now, SRT is a straight line.
(Linear pair)


...(i)
According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.
Using exterior angle theorem in triangle QRT, we get



Therefore, the value of x is 103 degrees.
Answer:
Y=21
Step-by-step explanation:
add 13 on both sides you get Y=21
Answer:
-14w+12
Step-by-step explanation:
10 - 7w - 13 - 7w + 15
Combine like terms
- 7w - 7w + 10-13+15
-14w+12
23 and 9 are the two numbers
Explanation:
x = one number
y = other number
x + y = 32 {sum of two numbers is 32
x - y = 14 {difference is 14}
-----------
2x = 46 {added the two equations together}
x = 23 {divided both sides by 2}
x + y = 32 {top equation}
23 + y = 32 {substituted 23, in for x, into top equation}
y = 9 {subtracted 23 from both sides}
23 and 9 are the two numbers
12x - 8y = -12
6x + 4y = -30
Multiply the 2nd equation by 2, to make the Y coefficients opposite:
6x + 4y = -30 x 2 = 12x + 8y = -60
Now add the two equations:
12x -8y = -12 + 12x +8y = -60
= 24x = -72
Divide bothe sides by 24 to solve for x:
x = -72/24
x = -3
Now replace x with -3 in the first equation to solve for y:
12(-3) - 8y = -12
-36 - 8y = -12
Add 36 to each side:
-8y = 24
Divide both sides by -8 to solve for y:
y = 24 / -8
y = -3
X = -3 and y = -3
(-3,-3)