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2 years ago

How do i solve 7x^{2} +11y^{2} =40

Mathematics

1 answer:

svetoff [14.1K]2 years ago

6 0

Answer:

Step-by-step explanation:

There is no solution as you have two variables and only one equation. The best you can do is solve for one variable as a function of the other.

$7x^2+11y^2=40\\ \\ 11y^2=40-7x^2\\ \\ y^2=\frac{40-7x^2}{11}\\ \\ y=\sqrt{\frac{40-7x^2}{11}}$

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The regular price of the soccer ball is $25. During the sale, it is 20 percent off. Use ratio reasoning to find x, the amount th

Evgen [1.6K]

$ 5 is taken is off the regular price

<em><u>Solution:</u></em>

Given that, Regular price of the soccer ball is $ 25

During the sale, it is 20 percent off

Let "x" be the amount that is taken off the regular price

Regular price = $ 25

Discount = 20 percent off

Which means, 20 % of regular price is taken off

x = 20 % of regular price

x = 20 % of 25

$x = \frac{20}{100} \times 25\\\\x = 5$

Thus $ 5 is taken is off the regular price

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3 years ago

Share £747 in the ratio 2:7

ivanzaharov [21]

Ratio: 2:7
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3 years ago

Read 2 more answers

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kow [346]

Answer:

m=17/40 $\frac{17}{40}$

Step-by-step explanation:

So you 5/7m - 1/7 = 9/56 $\frac{5}{7}m - \frac{1}{7} = \frac{9}{56}$

You Simplify both sides Then

well I Don´t know I hope this helped u, I tried ^^¨

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Step-by-step explanation:

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