A regular polygon<span> is equilateral (it has equal sides) and equiangular (it has equal angles). To find the </span>area<span> of a regular </span>polygon<span>, you use an apothem — a segment that joins the </span>polygon's<span> center to the midpoint of any side and that is perpendicular to that side (segment HM in the following figure is an apothem).</span>
59 is D
because with the point (-3,7) you substitute it into the equation, making it: 7=4x+b. solve for b. then you have y=4x+19. work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.
60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!
61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3
62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation.
but wait, you need a slope!
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!
63 is C. y= 1/2x+3
64 is B. (3, -5)
66 is B. negative. the line goes \ ( not / which is positive)
67 would be A. because it is positive and the I and the E are in the right places.
70 is C. 2/3. as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3
71 is D. y= 3x+10
72 is C. a third degree monomial
73 can't read
74 can't read
75 can't read.
Answer:
C
Step-by-step explanation:
New equation: y = -3(2y + 3) - 4
Distribute and simplify: y = -6y - 13
Add 6y: 7y = -13
Answer:
I don't really know but one triangle is 180 degrees so two added together is 360 degrees...
but ohh I remembered
a=c+d (since a+b=180 and c+d+b=180)
e=g+h (since e+f=180 and g+h+f= 180)
and the fact is that c+d+g+h+b+f=the angle sum of quadrilateral PQRS
a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)
a+e+b+f=360 (four angles are from one origin so it's 360 degrees )
