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Makovka662 [10]
3 years ago
14

Find the area of the isosceles triangle formed by points of intersection of the parabolas y=-x2+9 and y=2x2+3 and the origin.

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

10

Step-by-step explanation:

*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.

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olchik [2.2K]

Answer:

A=28.1\ cm^2

Step-by-step explanation:

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\displaystyle A=\frac{1}{2}r^2 \theta

<em>Note</em>: The angle must be in radians.

We need to find both the radius and the angle in radians.

Diameter = 9.6 cm

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\boxed{A=28.1\ cm^2}

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What is the value of X <br><br> Enter your answer in the box <br><br> X=
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Step-by-step explanation:

pythagorean theory or sohcahtoa or sin law

T = 60' and T = 45': S = 90' : T = 45' : R = 90'

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