Answer:
a) 0.71
b) 0.06
Step-by-step explanation:
We solve using Baye's Theorem
It is estimated that 88% of senior citizens suffer from sleep disorders and 7% suffer from anxiety. Moreover, 5% of senior citizens suffer from both sleep disorders and anxiety.
We have Two events
A and B
Events A = 88% of senior citizens suffer from sleep disorders
P(A) = 0.88
Event B = 7% suffer from anxiety
P(B) = 0.07
Moreover, 5% of senior citizens suffer from both sleep disorders and anxiety.
P(A and B) = 0.05
a)Given that a senior citizen suffers from anxiety, what is the probability that he or she also suffers from a sleep disorder? Round your answer to the nearest hundredth.
This is calculated as:
P(A and B)/P(B)
= 0.05/0.07
= 0.7142857143
Approximately = 0.71
B) Find the probability that a senior citizen suffers from anxiety, given that he or she has a sleep disorder. Round your answer to the nearest hundredth.
This is calculated as:
P(A and B)/P(A)
= 0.05/0.88
= 0.0568181818
Approximately = 0.06
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Answer: SO PROBABILITY IS LIKE YE</h3><h3>
LIKE ILL PROBABLE ANSWER THIS RIGHT OR ILL ANSWER IT WRONG</h3>
Step-by-step explanation:
I will maybe PROBABLY andswer this right or ill PROBABLY answer is wrong
Answer:
Therefore the correct answer is A.) 84.88%
Step-by-step explanation:
i) λ = 2
ii) λ for three units = 2 
3 = 6
iii) P(x ≥ 4) = 1 - P(x < 4) = 1 - {P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) }
= 1 - { 
}
= 1 - (0.0025 + 0.0149 + 0.0446 + 0.0892)
= 0.8488
Therefore the correct answer is A.) 84.88%
Answer:
1st quartile is 136
The second quartile is also the median 142
The third quartile is 162
The interquartile range is the difference between the 3rd and first quartile or 26
Step-by-step explanation:
