x - 15) \geqslant - 9(3 + x)" alt=" - (4x - 15) \geqslant - 9(3 + x)" align="absmiddle" class="latex-formula">
1 answer:
You might be interested in
Look at the picture.
The polygon is a right-angled trapezoid.
The area is:
The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.
The area is 39 square units.
The polygon is a right-angled trapezoid.
The area is:
The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.
The area is 39 square units.