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Lilit [14]
3 years ago
8

x - 15) \geqslant - 9(3 + x)" alt=" - (4x - 15) \geqslant - 9(3 + x)" align="absmiddle" class="latex-formula">
21 + x > 2( - 2 - 5x) + 6x
Mathematics
1 answer:
Kay [80]3 years ago
5 0

- (4x - 15) \geqslant  - 9(3 + x) \\  - 4x + 15 \geqslant  - 27 - 9x \\  - 4x + 9x \geqslant  - 27 - 15 \\ 5x \geqslant  - 42 \\ x \geqslant  - 8 \dfrac{2}{5}


21 + x > 2( - 2 - 5x) + 6x \\ 21 + x >  - 4 - 10x + 6x \\ x + 10x - 6x >  - 4 - 21 \\ 5x >  - 25 \\ x >  - 5

Hope this helps. - M
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Please notice that this kind of <em>exponential</em> function reports a <em>growth</em> for b > 1 and <em>decay</em> for b < 1 and b > 0. According to the statement we have the function y = 290 · 0.31ˣ, then we conclude that the exponential function given reports a <em>decay</em>.

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To learn more on exponential functions: brainly.com/question/11487261

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