Question

x - 15) \geqslant - 9(3 + x)" alt=" - (4x - 15) \geqslant - 9(3 + x)" align="absmiddle" class="latex-formula">
$21 + x > 2( - 2 - 5x) + 6x$

Answer 1

$- (4x - 15) \geqslant - 9(3 + x) \\ - 4x + 15 \geqslant - 27 - 9x \\ - 4x + 9x \geqslant - 27 - 15 \\ 5x \geqslant - 42 \\ x \geqslant - 8 \dfrac{2}{5}$


$21 + x > 2( - 2 - 5x) + 6x \\ 21 + x > - 4 - 10x + 6x \\ x + 10x - 6x > - 4 - 21 \\ 5x > - 25 \\ x > - 5$

Hope this helps. - M