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cestrela7 [59]
3 years ago
6

If you flip a coin and roll a

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer: 1/12

Step-by-step explanation:

Your outcome, 2H, divided by the total size of the output set. Thus gives you probability 1/12

Multiply the probability of Heads P(x=H | coin) = 1/2 . The probability of 2 P(x=2 | Die) = 1/6. Multiply 1/2(1/6) = 1/12.

Rufina [12.5K]3 years ago
6 0

Answer:

5/12

Step-by-step explanation:

khan

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There are 10,000 people at a concert.
frozen [14]

Answer:

62.5%

Step-by-step explanation:

Total number of people at the concert = 10000

Number of adults = 6250

Percentage of adults = number of adults/ total number of people at the concert x 100%

That’s

6250/10000 x 100%

0.625 x 100%

62.5%

62.5% of the people at the concert are adults

4 0
3 years ago
George is 4 times Dorothy's age. If George is 56, how old is Dorothy?
yarga [219]

56 \div 4 = 14
Dorothy is 14 years old



good luck
7 0
3 years ago
Read 2 more answers
8 k+d use k=2 and d=3​
sveta [45]

8×2=16

16+d

d=3

16+3=19

5 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
Pre cacl pleaseeeee help. the options are in the attachments as well
ivanzaharov [21]

Answer:

The values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of x so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is \pi. Then, the  vertical asymptotes associated with function cosecant are located in the values of x of the form:

x = 0\pm \pi\cdot i, \forall \,i\in \mathbb{N}_{O}

In other words, the values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

3 0
3 years ago
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