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3 years ago

Which is not a property of countercurrent multiplication?

Mathematics

2 answers:

laiz [17]3 years ago

6 0

Answer:

It is opposed by the vasa recta.

Step-by-step explanation:

krek1111 [17]3 years ago

5 0

Question:

Which of these is not a property of the renal counter-current multiplier?

It is opposed by the vasa recta.

It exploits the structure of the nephron loop.

It depends on active ion transport to function.

It creates a hyperosmotic interstitial fluid in the kidney medulla.

Answer:

The correct option is;

It is opposed by the vasa recta

Step-by-step explanation:

Counter current multiplication is the process whereby energy is used to build osmotic pressure gradient in the kidney such that water is reabsorbed from the exit tubular fluids reducing the volume of produced urine by increasing the urine concentration while the vasa recta capillaries slows blood flow rate so as to keep the osmotic pressure gradient constant enabling water to be reabsorbed thus concentrating the urine in line with counter current multiplication.

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Help me please i dont understand

matrenka [14]

Answer:

Step-by-step explanation:

The line where it says 2cm, extend that line to the top. You know have 2 triangles, call the one on the left A and the one on the right B

area of recntangle = bh

Rect A:

b = 5

h = 4 - 2

h = 2

bh = 5 x 2

bh = 10

Rect B:

b = 3

h = 4

bh = 4 X 3

bh = 12

Total = 10 + 12

Total = 22

5 0

1 year ago

the midpoint is AB is M(3,-2). One endpoint is A(7,-9). Find the coordinates of the other endpoint B.

cestrela7 [59]

Answer:

The required points of the given line segment are ( - 1, - 5 ).

Step-by-step explanation:

Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -

As we know that-

If a line segment AB is with endpoints ( $x_{1}, y_{1}$ ) and ( $x_{2}, y_{2}$ )then the mid points M are-

M = ( $\frac{ x_{1} + x_{2} }{2}$ , $\frac{ y_{1} + y_{2} }{2}$ )

Here,

Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -

then by the midpoint formula M are-

( 3, - 2 ) = ( $\frac{ 7 + x}{2}$ , $\frac{ - 9 + y}{2}$ )

On comparing x coordinate and y coordinate -

We get,

( $\frac{ 7 + x}{2}$ = 3 , $\frac{ - 9 + y}{2}$ = - 2)

( 7 + x = 6, - 9 + y = - 4 )

( x = 6 - 7, y = - 4 + 9 )

( x = - 1, y = -5 )

Hence the required points A are ( - 1, - 5 ).

We can also verify by putting these points into Midpoint formula.

8 0

3 years ago

In a study of preferences in leafcutter ants, a researcher presented 20 randomly chosen ant colonies with leaves from the two mo

Rufina [12.5K]

Answer:

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Step-by-step explanation:

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tyujftyu

yijy

8 0

3 years ago

I need helping solving -3z+7=-7-10z

Tpy6a [65]

-3z + 7 = -7 - 10z

Add 10z to both sides

7z + 7 = -7

Subtract 7 from both sides

7z = -14

Divide by 7

Z = -2

8 0

3 years ago

Read 2 more answers

2x-y=5 2x-2y=4 <img src="https://tex.z-dn.net/?f=2%20%5Ctimes%20%20-%20y%20%3D%205%20%5C%5C%202%20%5Ctimes%20%20-%202y%20%

d1i1m1o1n [39]

$\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right$

7 0

2 years ago