All categories

2 years ago

The difference of 4 and 5 times h

Mathematics

2 answers:

Tju [1.3M]2 years ago

4 0

Answer:

4-5h

Step-by-step explanation:

difference = minus sign

and 5 times h

Eddi Din [679]2 years ago

3 0

Answer:

Step-by-step explanation:

There are two answers to this making the question slightly ambiguous.

1) 4 - 5*h

2) (4 - 5)*h

It is impossible to tell which answer is the correct one. However, if I had to guess, I would say it is 4-5*h

You might be interested in

What is the greatest common factor of 18x^2 and 36x^2

KatRina [158]

2 is the greatest comun factor

3 0

2 years ago

Which of the following sequences of numbers are arithmetic sequences?

serg [7]

Hello,

A:no
B:no
C,D,E :yes

All you have to do : is the difference of next term and the term must be constant.

5 0

2 years ago

Read 2 more answers

CosA + cosB + cosC = 1 + 4sinA/2 sinB/2 sinC/2

bulgar [2K]

$\cos(A) + \cos( B ) + \cos(C) \\ = 2 \cos( \frac{A + B}{2} ) \cos( \frac{ A- B}{2} ) + 1 - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2\cos( \frac{\pi - C}{2} ) \cos( \frac{A - B}{2} ) - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2 \sin \frac{C}{2} \cos( \frac{A - B}{2} ) - 2 { \sin }^{2} \frac{C}{2} \\ = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \sin \frac{C}{2}] \\ = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \cos( \frac{A + B}{2} )] \\ = 1 + 2 \sin\frac{C}{2} \times 2 \sin( \frac{ \frac{A + B}{2} +\frac{A - B}{2} }{2} ) \sin( \frac{ \frac{A + B}{2} - \frac{A - B}{2} }{2} ) \\ = 1 + 4 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2}$

6 0

2 years ago

jaden writes for 3t minutes per night he also does a paper route for 23 minutes per night in 25 days how many minutes more he sp

vlada-n [284]

I'm pretty sure it would be 25 more minutes

4 0

2 years ago

Share £40 in the ratio 1:4 between Tim and Sam

Sauron [17]

Answer:

Tim gets £10 and sam gets £30

Step-by-step explanation:

7 0

2 years ago

The difference of 4 and 5 times h ​

The difference of 4 and 5 times h