Given the position function
<em>s(t)</em> = 3 - cos(<em>t</em> )
differentiate once to get the velocity, and twice to get the acceleration:
<em>v(t)</em> = <em>s'(t)</em> = sin(<em>t </em>) → <em>v</em> (4.3 s) ≈ -0.92
<em>a(t)</em> = <em>s''(t)</em> = <em>v'(t)</em> = cos(<em>t </em>) → <em>a</em> (4.3 s) ≈ -0.40
The acceleration is negative, so the particle is slowing down.
You can think of it as y=-(x-16)^2 to give you an upside down parabola with the center point at x=16 then knowing that the parabola's center is at a point 384m above the ground you can just add that to the equation, giving you y=-(x-16)^2+384.
Answer:
The answer to the question is b I think
Answer:
False
Step-by-step explanation:
Well it's True in a way, but they didn't simplify all the way. Correct simplification would be 1/3
