LCM of 2 and 5 =10
The LCM of 2 and 5 is the smallest positive integer 10 that is divisible by both 2 and 5 without any remainder.
Answer:
∫₁⁵ 2t (t² + t³) dt
Step-by-step explanation:
The area is ∫ₓ₁ˣ² y dx. To parameterize, replace x₁ and x₂ with t₁ and t₂. Replace y = f(x) with y = f(t), and replace dx with (dx/dt) dt.
x = 5 + t², so dx = 2t dt.
∫₁⁵ (t² + t³) (2t dt)
∫₁⁵ 2t (t² + t³) dt
The question "how much space is inside a solid?" is actually asking about the volume of that solid.
The volume of a cone is given by
where h is the height of the cone, and r is its radius.
So, you only need to plug in the values:
Answer: 1.5
Step-by-step explanation: you have to divide 6 by 4 and you get 1.5
Answer: The answer is 5a+13
Step-by-step explanation:
