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Diano4ka-milaya [45]

3 years ago

10

Which expression is equivalent to this expression? 4a + (–6b) – 3a + 2b A. a + 4b B. a – 4b C. 7a – 8b D. 7a – 4b Please Help! :

(

1 answer:

AleksAgata [21]3 years ago

4 0

Answer:

b. a-4b

Step-by-step explanation:

4a-3a=a

(-6b)+2b=-4b

combine these two and you get a-4b

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Determine whether each of these functions from Z to Z is one-to-one. a) f(n) = n - 1 b) f(n) = n2 + 1 c) f(n) = nº d) f(n) = [n/

sesenic [268]

Answer: The correct option is

(a) f(n) = n - 1.

Step-by-step explanation: We are given to determine whether the given functions are one-to-one or not.

We know that a function y = f(x) is one-to-one if and only if

f(x) = f(y) ⇔ x = y.

That is, any two distinct elements cannot have the same image.

(a) The given function is

$f(n)=n-1.$

Let us consider that

$f(n_1)=f(n_2)\\\\\Rightarrow n_1-1=n_2-1\\\\\Rightarrow n_1=n_2.$

Similarly,

$n_1=n_2\\\\\Rightarrow n_1-1=n_2-1\\\\\Rightarrow f(n_1)=f(n_2).$

So, this function is one-to-one.

(b) The given function is

$f(n)=n^2+1.$

Let us consider that

$f(n_1)=f(n_2)\\\\\Rightarrow n_1^2+1=n_2^2+1\\\\\Rightarrow n_1^2=n_2^2\\\\\Rightarrow n_1=\pm n_2.$

That is, there may be two unequal elements having same image.

For example, f(-1)=(-1)²+1=1+1=2, f(1)=(1)²+1=1+1=2.

It implies that f(-1)=f(1) but 1 ≠ -1.

So, the given function is not one-to-one.

(c) The given function is

$f(n)=n^0.$

Here, the image of all the elements is 1.

For example, $f(2)=2^0=1,~~f(3)=3^0=1.$

f(2)=f(3) but 2≠3.

So, more than one element is having the same image and so the function cannot be one-to-one.

(d) The given function is

$f(n)=\left[\dfrac{n}{2}\right].$

Here, we see that

$f(2)=\left[\dfrac{2}{2}\right]=[1]=1,\\\\\\f(3)=\left[\dfrac{3}{2}\right]=[1.5]=1.$

So, f(2)=f(3) but 2≠3.

So, the given function is not one-to-one.

Thus, the correct option is (a).

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Marylou buys a package of 500 jewels for her jeans. She uses the same number of jewels for each pair of jeans. How many jewels w

Gnom [1K]

HOW MANY PAIRS OF JEANS DOES SHE HAVE? Based on the merits, here it is

ASSUMING SHE HAS 5O PAIRS OF JEANS

$j \: = jewels\\ 50(j) \leqslant 500 \\ 10 \: jewels \: on \: eavh \: pair$
ASSUMING WE DON'T KNOW HOW MANY PAIRS OF JEANS SHE HAS

$j \: = jewels \\ p = pairs \: ofjeans\\ (p) \times (j) \leqslant 500 \\ (j )\: \: jewels \: on \: eavh \: pair \: of \: her \: (p) \: total \: jeans$

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3 years ago

Help me pleaaseee!!!!!

jarptica [38.1K]

Answer: 5^7

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4 years ago

Read 2 more answers

What is 136°=92°+6r+2°

Lina20 [59]

What is being solved for is r.

$136 = 92 + 6r + 2$

$136 - 92 - 2 = 6r$

$42 = 6r$

$r = 6$

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3 years ago