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3 years ago

Given quadrilateral ABCD is a rhombus, find AC and EB.

Mathematics

2 answers:

Westkost [7]3 years ago

8 0

Answer:

AC = 18, EB = 5

Step-by-step explanation:

In a rhombus, AE = CE, and DE = BE. However, AE or AC ≠ DE or BE.

CE = AE

= 9

AC = CE + AE

= 9 + 9

= 18

DE = BE

= 5

trasher [3.6K]3 years ago

3 0

Answer:

AC = 18

EB = 5

Step-by-step explanation:

give me brainliest

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notka56 [123]

Solving:
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<span>Replace denominators and resolve:
</span> $\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}$
$\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}$
Cancel the dominators
$\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}$
$3(3+4x) + 2(5-x) = 29$
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$\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark$

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