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Marta_Voda [28]

2 years ago

8

Which additional piece of information would allow you to

1 answer:

Amanda [17]2 years ago

5 0

Answer:

another leg

Step-by-step explanation:

bc thats fax

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erastovalidia [21]

Answer:

68.06%;

Step-by-step explanation:

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2 years ago

If i put a penny in a jar every day for a year how much money will i have

katovenus [111]

Hi there!

A year is 365 days, correct?
If we save our pennies up from January 1st to December 31st, you'd have 3 dollars (since 100 pennies is 1 dollar) and 65 pennies left over. If it was a leap year, however, you'd have 3 dollars and 66 cents. :)

Hope this helps! :D

7 0

3 years ago

M and n are parallel lines cut by a transversal.<br> What is the value of x + y?

slava [35]

Answer:

180°

Step-by-step explanation:

It will be answer ...............

8 0

3 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

100PT AND BRAINLIEST! PLEASE HELP! Use technology to approximate the solution(s) to the system of equations to the nearest tenth

N76 [4]

Answer:

C. (0.9, 0.3)

Explanation:

$\rightarrow \sf \dfrac{1}{4^{x}} = \log(2x)$

The above given equation is critical to solve algebraically thus they have mentioned to solve it using a technology - graphing calculator.

<h3><u /></h3><h3><u>When graphed the following equations</u>:</h3>

They meet each other at: (0.9371, 0.2728) $\sf \underset{ solution }{ \xrightarrow{ \text{ nearest tenth } } }$ (0.9, 0.3)

8 0

2 years ago

Read 2 more answers