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lions [1.4K]
3 years ago
14

A triangle with side lengths of 12in 16in and 24 inches is a right triangletrue or false​

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

False.

Step-by-step explanation:

The legs of a right triangle must have equal lengths and none of these are the same length.

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What value of x is the solution of the equation 1/7+2x/3 = 15x-3/21?
lana66690 [7]
1/7+2x/3=(15x-3)/21  make all terms have a common denominator of 21

3+14x=15x-3  subtract 3 from both sides

14x=15x-6  subtract 15x from both sides

-x=-6 divide both sides by -1

x=6

*Notice the use of parentheses in this format to make it clear what the numerators and denominators are...

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There are 5000 books in the​ town's library. Of​ these, 4,000 are fiction. To find the percent of the books that are​ fiction, f
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80%

Step-by-step explanation:

4000 / 5000 * 100 = 80%

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Jennifer needs to use a ladder to clean a second floor window on a building. If the window is 13 ft above the ground and the bas
BigorU [14]

By using the Pythagoras theorem, the length of the ladder will be 13.6 feet.

<h3>What is a Pythagoras theorem?</h3>

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

Jennifer needs to use a ladder to clean a second-floor window on a building.

If the window is 13 ft above the ground and the base of the ladder is 4 ft from the building.

Then the length of the ladder will be

H² = 13² + 4²

H² = 169 + 16

H² = 185

H = 13.6 ft

More about the Pythagoras theorem link is given below.

brainly.com/question/343682

#SPJ1

7 0
2 years ago
Question 15 (1 point)
yawa3891 [41]

Answer:

B) Variable Expense

Step-by-step explanation:

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8 0
3 years ago
Consider a population of Pacific tree frogs (Pseudacris regilla). In this population of frogs, a single locus controls the produ
zloy xaker [14]

Answer:

Step-by-step explanation:

Hello!

Use these data to calculate the chi-square statistic. Report your calculated chi-square statistic to two decimal places.

In this example, the study variable is X: genotype of a single locus two allele gene that codes the mating call of tree frogs. Categorized: S₁S₁, S₁S₂, and S₂S₂.

Usually, when you have a sample of observed genotypes of a gene of interest, the goal is to check if these genotypes follow a theoretical model such as the frequency models proposed by Mendel.

In Mendelian genetics, when two heterozygous individuals (Aa, Aa) from the F1 generation are crossed, you expect the next generation (F2) to show the genotypic ratio 1:2:1 ⇒ This model means that out of 4 descendants 1 will have the genotype AA, 2 will have the genotype Aa and 1 will have the genotype aa. Since there is no theoretical model specified I'll use the mendelian ratio 1:2:1.

If this theory applies to the population then we'll expect that the proportion of the first genotype is P(S₁S₁)= 0.25, the second P(S₁S₂)= 0.5 and the third P(S₂S₂)=0.25

To test if the observed genotypes follow the theoretical model you have to apply a Chi-Square Goodness of Fit Test.

For this test the hypotheses are:

H₀:P(S₁S₁)= 0.25; P(S₁S₂)= 0.5; P(S₂S₂)=0.25

H₁: The data is not consistent with the specified distribution.

α: 0.05

Statistic: X^2= sum(\frac{(o_i-e_i)^2}{e_i} )~X^2_{k-1}

Where:

oi: Observed frequency for the i- category

ei: Expected frequency for the i-category

k= number of categories

The rejection region for this test is one-tailed to the right. This is so because if the observed and expected values are too different (the chi-square value will be high) this will mean that the population doesn't follow the theoretical model and thus reject the null hypothesis. If the differences between what's observed and what's expected are small, this will mean that the population follows the theoretical model (and you'll obtain a small chi-square value) and you will not reject the null hypothesis.

The critical value is:

X^2_{k-1; 1 - \alpha }= X^2_{3;0.95}= 7.815

If the statistic is at least 7.815, the decision is to reject the null hypothesis.

If the statistic is less than 7.815, the decision is to not reject the null hypothesis.

Step 1 is to obtain the expected frequencies for each category:

e_i= n*P_i

e_{S_1S_1}= n * P(S_1S_1)= 1341*0.25= 335.25

e_{S_1S_2}= n * P(S_1S_2)= 1341 * 0.5= 670.5

e_{S_2S_2}= n * P(S_2S_2)= 1341*0.25= 335.25

Note: the summatory of the expected frequencies is equal to the total of observations ∑ei= n. If you have doubts about your calculations, you can add them to check it: ∑ei= 335.25 + 670.5 + 335.25= 1341

X^2= (\frac{(987-335.25)^2}{335.25} )+(\frac{(333-670.5)^2}{670.5} )+(\frac{(21-335.25)^2}{335.25} ) = 1731.50

Decision: Reject null hypothesis.

I hope this helps!

3 0
3 years ago
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