All categories

2 years ago

Plz help! will mar brainliest.

Mathematics

2 answers:

OleMash [197]2 years ago

4 0

Answer:

From -2<x<-1, the function F(X) is increasing. (B)

Really, it increases all from around -2.5<x<0.5

C is also the second answer, as it increases til around 2.5

It is decreasing from -4<x<-3. But increases right after. It then starts to slow down around x = 1 and go down again.

Which means (B) is your answer.

If you want to get fancy, its a polynomial and if you take the derivative for instantaneous rate, you will see f prime is increasing if you make an example function.

Scorpion4ik [409]2 years ago

4 0

Answer:

-2,5 < x < 1

is the simplified and truncated value

Step-by-step explanation:

You might be interested in

HI i neeed helppppppppppppppppp

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A cyclist rides at an average speed of 31 miles per hour. The cyclist’s speed, s, can differ from the average by as much as 8 mi

Shalnov [3]

In this compound inequality X should be 8.

4 0

3 years ago

Read 2 more answers

Triangle ABC was transformed to be triangle FED using

vampirchik [111]

Answer:

the triangle was rotated about 90 degrees i think

4 0

2 years ago

How to simplify 8x2+7x-3+4x-8

Mazyrski [523]

Hello :
<span>8x²+7x-3+4x-8 = 8x² +(7x+4x) +(- 3 - 8)=8x²+7x - 11</span>

6 0

3 years ago

Find the global maximum and global minimum values (if they exist) of x 2 + y 2 in the region x + y = 1. If there is no global ma

Grace [21]

Given that $x+y=1$ , we have $y=1-x$ , so that

$f(x,y)=x^2+y^2\iff g(x)=x^2+(1-x)^2$

Take the derivative and find the critical points of $g$ :

$g'(x)=2x-2(1-x)=4x-2=0\implies x=\dfrac12$

Take the second derivative and evaluate it at the critical point:

$g''(x)=4>0$

Since $g''$ is positive for all $x$ , the critical point is a minimum.

At the critical point, we get the minimum value $g\left(\frac12\right)=f\left(\frac12,\frac12\right)=\frac12$ .

5 0

3 years ago