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4 years ago

10

WILL GIVE BRAINLYEST

2 answers:

tia_tia [17]4 years ago

5 0

I'm pretty sure it would be 14:854

DanielleElmas [232]4 years ago

4 0

The answer is hours. Its dumb but that's the right answer....

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The sum of r and t is equal to 42. Let r = 25. What is the value of t?

Anni [7]

R + t = 42
r = 25

Plug in 25 for r

(25) + t = 42

Isolate the t by subtracting 25 from both sides

t + 25 (-25) = 42 (-25)
t = 42 -25
t = 17

Hope this helps

8 0

3 years ago

Read 2 more answers

Add lunch five friends share three pizzas equally what fraction of the pizza does each friend get

Hitman42 [59]

how many slices does each pizza have? anyways if its 8 (normally)

8 x 3 = 24 / 5 = 4.2 slices each

or nah?

5 0

3 years ago

I have four identical oranges. How many ways are there for me to divide these oranges into at most three groups?

Alina [70]

Answer:

"At most" connotes 1, 2 or 3 groups

For one group = one way....all of them together

For two groups.....2 + 2 or 3 + 1 = two ways ...{the oranges are indistinguishable, so 1 + 3 is the same grouping as 3 + 1 }

For 3 groups = 1 + 1 + 2 = one way {again, they are indistinguishable}

So ….. four ways.....

Step-by-step explanation:

5 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

7] reflect (4,8) across x = 1 line

shusha [124]

Answer: (4,-8)

Step-by-step explanation:

Bc reflect over x = (x,-y)

5 0

4 years ago

Read 2 more answers