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Monica [59]
3 years ago
12

Do yall know what point B is need help ASAP

Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer:

(0,-2)

Step-by-step explanation:

i got you fam

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The first one is brainlyist
bearhunter [10]

Answer:

Step-by-step explanation:

6 0
2 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
In PE class Flynt is choosing 2 members for his dodgeball team. If he can choose 2 individuals from a group of 6 classmates, how
Tatiana [17]

Answer:

C) 15

Step-by-step explanation:

Here we have to use the combination to find the number of possible combinations.

Total number of classmates (n) = 6

We are selecting 2 individuals. So r = 2.

The combination formula nCr = \frac{n!}{r!(n-r)!}

Plug in n = 6 and r =2, in the above formula, we get

= \frac{6!}{2!(6-2)!}

= \frac{6!}{2!4!}

Simplifying the above factorial, we get

= 15

So the answer is C) 15

7 0
3 years ago
Read 2 more answers
You have a rectangular yard that measures 16 feet Long by 14 feet wide.it id covered in grass except For in the Center,where the
BartSMP [9]
A of the yard= L*l=16*14=  224 feet²

A of the fountain= πR²

d=2R
4=2R

R=4:2=2

A of the fountain= 2²π=4 *3,14= 12,56 feet²

A of the grass portion= 224-12,56=  211,43 feet²

answer d)211,43 feet²
5 0
3 years ago
-4^6•4^2/4^4<br><br> Simplify
elena-14-01-66 [18.8K]

Answer:

-4^{4}

Step-by-step explanation:

Reduce the expression -4^2×4^2

Calcualte the product and you get -4^4

If you want the alternative form is will be -256

Hope this helpsʕ•ᴥ•ʔ

6 0
3 years ago
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