Answer:
f(x) is concave up whenever:
B. 3x²−10 is positive
f(x) is concave down whenever:
A. 3x²−10 is negative
The points of inflection of f(x) are the same as:
B. the zeros of 3x²−10
Step-by-step explanation:
Given the function f(x) = 1 / (x²+10)
We can determine the concavity by finding the second derivative.
If
f"(x) > 0 ⇒ f(x) is concave up
If
f"(x) < 0 ⇒ f(x) is concave down
Then
f'(x) = (1 / (x²+10))' = -2x / (x²+10)²
⇒ f"(x) = -2*(10-3x²) / (x²+10)³
if f"(x) = 0 ⇒ -2*(10-3x²) = 0 ⇒ 3x²-10 = 0
f(x) is concave up whenever 3x²−10 > 0
f(x) is concave down whenever 3x²−10 < 0
The points of inflection of f(x) are the same as the zeros of 3x²-10
it means that 3x²-10 = 0
It would travel 3.0 x 10 ^ 10th power
Answer:
c 
Step-by-step explanation:
![113,391 = 4\frac{9}{10}[2\frac{1}{10}]^{2} + 135 \\ \\ 113 ≈ h](https://tex.z-dn.net/?f=113%2C391%20%3D%204%5Cfrac%7B9%7D%7B10%7D%5B2%5Cfrac%7B1%7D%7B10%7D%5D%5E%7B2%7D%20%2B%20135%20%5C%5C%20%5C%5C%20113%20%E2%89%88%20h)
I am joyous to assist you anytime.
I believe the commission is 7,511
It would be 29 or if you multiply it would be different
