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LiRa [457]
2 years ago
7

X2 - x - 42 a=? b=? C=? help me ​

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
6 0

Step-by-step explanation:

thr standard form for a quadratic equation is:

ax²+bx+c

in this example, a=1, b=(-1), c=(-42)

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An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.
lawyer [7]

Answer:

7.5cm²

Complete question:What is the surface area of the 8-sided figure?

Step-by-step explanation:

Consider the half of the 8-sided die i.e the pyramid ABCDE:

As the base is 6 of the perimeter, so each side of the base is 6/4=3/2

Now, the distance between the tallest points is 2 cm, so the height of Pyramid ABCDE is 1 cm.

Considering the right triangle EOM:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is 

\sqrt{1+ ( \frac{3}{4} )^{2} }=  \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}   (cm)

5. So side EBC has area  

\frac{1}{2}BC*EM=  \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}

6. The total area is 8*Area(EBC)=8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )

3 0
3 years ago
a countrys population in 1991 was 145 million. in 1996 it was 151 million. estimate the population in 2006 using the exponential
andrew-mc [135]

Answer:6 billion

Step-by-step explanation:

Just multiple both numbers

8 0
3 years ago
F^3 x f^9 x f^4 <br> Simplify
Hatshy [7]

Answer:

f¹⁶

Step-by-step explanation:

f³*f⁹*f⁴

f⁽³⁺⁹⁺⁴⁾

f¹⁶

6 0
3 years ago
Two parallel lines are cut by a transversal. What is the measure of 26?
Alborosie
The measure of 6
Is B
7 0
3 years ago
Integrate dx/3sinx+4cosx
german

\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}

A standard approach would be the tangent half-angle substitution:

t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx

Then

\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}

\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}

from which we get

\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt

So the integral becomes

\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}

Rewrite the denominator as

2t^2-3t-2=(2t+1)(t-2)

and expand the integrand into its partial fractions:

\dfrac1{2t^2-3t-2}=\dfrac15\left(\dfrac1{t-2}-\dfrac2{2t+1}\right)

We have

\displaystyle-\frac15\int\frac1{t-2}-\frac2{2t+1}\,\mathrm dt=-\frac15(\ln|t-2|-\ln|2t+1|)+C

=\dfrac15\ln\left|\dfrac{2t+1}{t-2}\right|+C

=\dfrac15\ln\left|\dfrac{2\tan\frac x2+1}{\tan\frac x2-2}\right|+C

6 0
3 years ago
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