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Flura [38]
3 years ago
6

Acellus

Mathematics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

(-2, 3)

Step-by-step explanation:

Think of this in the future:

Counter-clockwise rotations:

90-degree --> (x,y) = (-y,x) ex. (3,2) --> (-2,3)

180-degree --> (x,y) = (-x,-y) ex. (3,2) --> (-3, -2)

270 degree --> (x,y) = (y,-x) ex. (3,2) --> (2, -3)

Clockwise rotations:

90-degree --> (x,y) = (y, -x) ex. (3,2) --> (2, -3)

180-degree --> (x,y) = (-x,-y) ex. (3,2) --> (-3,-2)

270-degree --> (x,y) = (-y, x) ex. (3,2) --> (-2,3)

DiKsa [7]3 years ago
7 0
The answer is in the teacher
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Describe the graph of the function. y = |x - 4| - 7
ANTONII [103]

Answer:

Step-by-step explanation:

The graph is that of the basic absolute value function y = |x|, except that the vertex (0, 0) has been translated 4 units to the right and 7 units down.

6 0
3 years ago
I WILL GIVE YOU BRAINLIEST IF YOU ANSWER THE WHOLE QUESTION.
kicyunya [14]

Answer:

B)y=2x   and     C) y=-7x+9

Step-by-step explanation:

Once a linear function has a constant rate of change, you just have to find the linear functions. Also, the other ones are quadratic functions, and their graph are parabolas, which don't have a constant rate of change.

Considering f(x)=y

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5 0
3 years ago
Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (0, 5) and point (3, -1) rounded to
miss Akunina [59]

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answer (a)

5 0
3 years ago
Using the sas congruence theorem Given: JK || LM , JK ≅ LM L is the midpoint of JN Prove: JKL ≅ LNM
pshichka [43]

Answer: 1.JK || LM= Given

2.JK=LM=Given

3. L is the midpoint of JN = Given

4. LN=JL = Defintion of midpoint

5.<LJK=NLM = Corresponding angles theorem

6.△JLK=△LNM = SAS

Step-by-step explanation:

8 0
3 years ago
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2t−5=−10<br><br> Helpppppp<br><br> Plz
likoan [24]

Answer:

t= -2.5

Step-by-step explanation:

2t−5=−10

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2t= -5

divide by 2

t= -2.5

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3 years ago
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