The area of a rectangle is 60 square inches. If the width is 15 inches, what is the length?

Mathematics

2 answers:

vekshin13 years ago

6 0

Answer:

If Z is the centroid of RST , RZ = 42, ST = 74, TW = 51, ZY = 23 and find each measure. 4. If E is the circumcenter of MNP , find each measure. If Z is the centroid of RST , RZ = 42, ST = 74, TW = 51, ZY = 23 and find each measure. 4. If E is the circumcenter of MNP , find each measure.

Step-by-step explanation:

ss7ja [257]3 years ago

3 0

Answer: 4in

Step-by-step explanation:

Length = Area / Width

L = 60/15

L = 4inches

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Which two values of x are roots of the polynomial below? x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

Solution:

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$