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JulsSmile [24]
4 years ago
12

Write the expression as a single natural logarithm. 3 In 4 + In 5

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
4 0
Huh? that is difficult I have no idea
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Write in detail how you have used math in the real-world to solve a problem.
neonofarm [45]

Answer:

I went shopping once for ingredients of a cake, but i didn't know what my finale price would be. So i estimated what the total cost could be, then i took all the prices and added them up then divided the price by how many ingredients i got to find the average and it was pretty close to my estimate. So math can help when you go shopping. (Sorry if how i find my prices is weird, i kinda just stand in one spot for at least 5 - 8 mins trying to find my price)

Step-by-step explanation:

3 0
3 years ago
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What is an expression equivalent to 4d-4?
hoa [83]

4(d-1), if you expand it gets 4d-4.


8 0
3 years ago
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Convert 8.9cm to kilolitres​
masha68 [24]
8.9 × 10-6 kiloliter. 8.9e-6
7 0
3 years ago
Simplify square root of 3 multiplied by the fifth root of 3.
almond37 [142]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}\qquad\qquad %  radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}} \\\\


\bf -----------------------------\\\\
thus\qquad \sqrt{3}\cdot \sqrt[5]{3}\implies \sqrt[2]{3^1}\cdot \sqrt[5]{3^1}\implies 3^{\frac{1}{2}}\cdot 3^{\frac{1}{5}}
\\\\\\
3^{\frac{1}{2}+\frac{1}{5}}\implies 3^{\frac{7}{10}}\implies \sqrt[10]{3^7}\implies \sqrt[10]{2187}
5 0
3 years ago
It is not possible to prove one pair of triangles congruent and then use their congruent corresponding parts to prove another pa
borishaifa [10]

Answer:

true

The wording does not quite mean anything,

but what I think was meant to ask is

"if we use some parts of two triangles to prove they are congruent,

can we then use that to prove that

a pair of corresponding parts not used before are congruent?"

The answer is

Yes, of course,

Corresponding Parts of Congruent Triangles are Congruent,

which teachers usually abbreviate as CPCTC.

For example, if we find that

side AB is congruent with side DE,

side BC is congruent with side EF, and

angle ABC is congruent with angle DEF,

we can prove that triangles ABC and DEF are congruent

by Side-Angle-Side (SAS) congruence.

We then, by CPCTC, can conclude that other pairs of corresponding parts are congruent:

side AB is congruent with side DE,

angle BCA is congruent with angle EFD, and

angle CAB is congruent with angle FDE.

It was possible (by CPCTC) to prove those last 3 congruence statements,

after proving the triangles congruent.

The expected answer is FALSE.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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