Answer:
369.7 mL of medication
Step-by-step explanation:
How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?
From the above question,
The dosage of the medication =
2.5 tsp 3 times a day
= 2.5 × 3 = 7.5 tsp per day.
Since
1 day = 7.5 tsp
10 days = x tsp
Cross Multiply
x = 10 × 7.5 tsp
x = 75 tsp of medication for 10 days.
Step 2
It is important to note that:
1 tsp = 4.929 mL
75 tsp = x mL
Cross Multiply
x = 75 × 4.929 mL
x = 369.669 mL of medication
Approximately = 369.7 mL of medication
a. At its maximum height, the ball has zero vertical velocity, so


b. The ball's height in the air
at time
is given according to

Solve for
when
:

Answer:
z = 55.15432893
x = 59.61543424
y = 22.5166605
Step-by-step explanation:
To find length "z" you will have to use SOHCAHTOA.
Labelling the triangle will show us that the side marked "z" is the hyp and the side marked 39 is the opp.
sin 45 = 
z sin 45 = 39
z = 
z = 55.15432893
Using Pythagoras' theorem, you can find that the adj = 39
In the other triangles POV, the adj is actually the opp.
Therefore, use tangent to find y.
tan 60 = 
y tan 60 = 39
y = 
y = 22.5166605
Use Pythagoras's Theorem to find x.

A) A (1,-1)
b) P' (3,1)
c) Rule: (x, y) → (x + 2, y - 1)