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s2008m [1.1K]
3 years ago
7

A high speed train in Japan,known at "mini-Shinkansen", can travel at constant speed at 160 miles in two hours.Would the train b

e able to travel 648 miles in 8 hours explain how you know using unite rate
Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

N0.

Step-by-step explanation:

In 1 hour it can travel 160/2 = 80 miles.

So in 8 hours it travels 8 * 80 = 640 miles only.

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50.27 = 4 * PI * r^2
</span></span></span>
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r = sq root (<span> <span> <span> 4.0003594946)

radius = </span></span></span> <span> <span> <span> 2.0000898716 </span> </span> </span>

So the diameter = <span> <span> <span> 4.0001797433 </span> </span> </span>

or it is roughly 4 feet


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Amiya got a 95% on her test
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Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

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I need help with this
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Answer:

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