Answer:
15
Step-by-step explanation:
Let n(T) denotes total surveys done i.e. n(T)=140
Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71
Let n(B) be the no. of side effects i.e.n(B) =60
Let n(C) be the no. of responses to cost i.e. n(C)= 65
33 responded positively to both effectiveness and side effects
So, n(A∩B)=33
31 to effectiveness and cost
n(A∩C)=31
28 to side effects and cost
n(B∩C)=28
21 to none of the items
So, n(A∪B∪C)=140-21 = 119
we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)
Formula:
n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)
119=71+60+65-33-31-28+ n(A∪B∪C)
119=104+ n(A∪B∪C)
119-104= n(A∪B∪C)
15= n(A∪B∪C)
Hence 15 responded positively to all three
so all angles of a triangle are going to add up to 180°
<u>so for L</u>
20 + 72 + x = 180
92 + x = 180
180 - 92 = 88
<u>For I</u>
56 + 89 + x = 180
180 - 145 = 35
<u>For C</u>
28 + 128 + x = 180
180 - 156 = 24
<u>For D</u>
122 + 38 + x = 180
180 - 160 = 20
Right so it would be 509 sq ft
Answer:
a) 83%
b) 0.892
Step-by-step explanation:
percentage that attends class on friday = 74%
percentage that pass because they attend class on friday = 88%
percentage that pass but did not go to school on friday = 20%
a) percentage of students expected to pass the course
= (74% x 88%) +(88% x 20%)
= 0.6512 + 0.176
= 0.8272
= 83%
b) If a person passes the course, what is the probability that he/she attended classes on Fridays
= 74% divided by 83%
= 0.892
