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Harrizon [31]
2 years ago
15

On a baseball field the infield area created by the baselines is square. In a youth baseball league this area is 3600 square fee

t. A pony league of younger children use a smaller field with a distance between each base 20 feet less than the youth league. What is the distance between each base for the pony league?
Mathematics
1 answer:
guajiro [1.7K]2 years ago
6 0
You divide 3600/20,ad you will get 180 square feet.
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Help me please i dont understand
kipiarov [429]

Answer:

C=75.36

A=452.16

Step-by-step explanation:

C=2x3.14xr

2×\pi×12=75.36

A=3.14×r^{2}

3.14x12x12=452.16

5 0
3 years ago
Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
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Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
3 years ago
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Answer:

Step-by-step explanation:

What you would want to do is add the $15.75 you would want to add it 5 times

8 0
2 years ago
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When Javier writes 40 on both accounts they cost him the same amount of money so it should be 41.

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150s or 2 min and 30 s

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5 0
3 years ago
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