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Alexxx [7]
2 years ago
11

What is the solution to the equation 4x + 2(x − 2) = 4x + x − 12? (1 point)

Mathematics
1 answer:
Anettt [7]2 years ago
3 0

Answer:

It's   -8

Step-by-step explanation:

DISTRIBUTE :

4x + 2( x - 2 ) = 4x + x - 12

4x + 2x - 4 = 4x + x - 12

COMBINE LIKE TERMS :

4x + 2x - 4 = 4x + x - 12

6x - 4 = 4x + x - 12

COMBINE LIKE TERMS :

6x - 4 = 4x + x - 12

6x - 4 = 5x - 12

ADD 4 TO BOTH SIDES :

6x - 4 = 5x - 12

6x - 4 + 4 = 5x - 12 + 4

ADD THE NUMBERS/ SIMPLIFY :

6x = 5x - 8

SUBTRACT 5x FROM BOTH SIDES :

6x = 5x - 8

6x - 5x = 5x - 8 - 5x

SIMPLIFY :

x = -8

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Claire wants to start a stamp collection. She spends $15 on an album to hold her stamps and $1.25 for each stamp. If she has $40
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Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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